... his units. The correct result: the circumference of the

**tire**is 0.58 pi meters, the speed is 17 meters per second, so the**rotation**speed is 17/(0.58 pi) revolutions per second. The...6 Answers · Science & Mathematics · 05/08/2008

... every second then this divided by the circumference of the tyre will give the

**frequency**of**rotation**. a) 10/1.69338 = 5.89 rps to 2 decimal places (note this is...3 Answers · Science & Mathematics · 31/07/2011

...ac = (v)^2 / r = r(w^2) You need to find the angular speed using the

**frequency**(9 rotations per second) and the number of radians in the**tire**(2 times pi).1 Answers · Science & Mathematics · 15/08/2009

... circumference of the

**tire**is moving at 24.9m/s. The rotational speed of the**tire**is v/r = 24.9/(.591/2) = 21.07 rad/sec In rpm, = 21.07* 1 rev...1 Answers · Science & Mathematics · 25/09/2012

...;= IF the speedometer reading was DETERMINED by the

**frequency**{f} of**rotation**of the wheels THEN the radius of the tires would NOT matter. IMHO this is a misleading sentence...3 Answers · Science & Mathematics · 02/02/2013

... example, at a typical driving speed of 50mph, typical forcing frequencies due to the

**rotation**of the tyres are about 10 Hz. If a car vibrated a lot when ...1 Answers · Science & Mathematics · 31/12/2013

... of a second. So if the

**tire**is turning clockwise and the .... This interaction between two frequencies (**rotation frequency**and camera**frequency**in this case) is...1 Answers · Science & Mathematics · 04/06/2010

...acceleration there is a similar rotational equation. Furthermore, position --> angle velocity --> angular

**frequency**acceleration --> angular acceleration... The radius of the**tire**would allow you to calculate the position...1 Answers · Science & Mathematics · 19/11/2010

... around its hub. As the

**tire**is rotating, all the points...angular velocity in radians/sec. f is the**frequency**of the**rotation**in cycles per second were 1 cycle...2 Answers · Science & Mathematics · 26/04/2010

..., and inside the tubing of your bicycle

**tire**. When that rotates, you get pressed... / T = 2 pi R f, where f is the**frequency**(the number of revolutions per unit of time...1 Answers · Science & Mathematics · 10/06/2011