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CBD = 308 degrees

**TCB**= 270 degrees1 Answers · Science & Mathematics · 22/10/2016

They have used OA + sBA +

**tCB**which is also perfectly valid. You can use ANY two vectors in the plane as long as they are not parallel2 Answers · Science & Mathematics · 07/09/2010

arc TC = 128 ( given) arc TBD = 90 + 90 = 180 arc BTC = 90 + 128 = 218 arc

**TCB**= 360 - 90 = 2701 Answers · Science & Mathematics · 29/06/2010

...vertical pole TD. Angle TBD = 35 degrees Angle

**TCB**= 50 degrees BC = 10 Let CD = x and TD...1 Answers · Science & Mathematics · 31/08/2011

...3) pihr^2 You have height of the bottom part. Look at the right triangle

**TCB**where T = tip of the cone, C center of the base, and B is...1 Answers · Science & Mathematics · 20/05/2014

since TB is a quarter circle, then TB = 90° thus

**TCB**= 360° - 90° TDC = 360° - 128° i think also that angle BPD is a right angle....1 Answers · Science & Mathematics · 21/03/2010

... TAC is 58°. Angle TCA = Angle

**TCB**= 90°. Angle TBC is not given. Horizontal...1 Answers · Science & Mathematics · 19/02/2011

...triangle) ACT = ABC = 49° (inscribed in same segment as ABC)

**TCB**= 49° + 41° + 38° = 128° (sum of its parts) RCB = 180° -**TCB**...2 Answers · Science & Mathematics · 25/01/2011

You've got to be kidding me... I sincerely hope you fail.

2 Answers · Science & Mathematics · 05/11/2012

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