STP = standard Temperature and pressure This is T = 0 deg Celcius (273.15 K) and P = 1.0 atm At STP 1 mole of any ideal gas has a volume of 22.4 L. So ...
4 Answers · Science & Mathematics · 26/09/2009
...1 mole any ideal gas occupies a volume of 22.4 L at STP moles gas = 0.258 L / 22.4 L/mol = 0.011518...g / 1.008 g/mol = 8 mol H in 1 mol gas So molecula formula C4H8
1 Answers · Science & Mathematics · 28/02/2010
formula : T2PV=TP2V2.....P2=T2PV/TV2 know: (101.3 kpa...
2 Answers · Science & Mathematics · 01/06/2010
STP is standard temperature and pressure. the temp is 273 kelvin, and pressure is 101.3 kpa. im not 100% sure on the first question, but for the 2nd one, you use the formula PV =nRT Pressure = 101.3 Volume = They don't give it to you so thats...
2 Answers · Education & Reference · 20/09/2009
try to use this website www.easy-converter.com its much easier hope that will help.....good luck
1 Answers · Science & Mathematics · 29/09/2012
...we assuming stp ? if so, d=m/v. v=22.4L (at stp ), so rearrange the question to solve for m. m=d*v. 1.17 g/...get the first answer. if it is 1, the molecular formula is the empirical formula , otherwise the molecular formula ...
3 Answers · Education & Reference · 07/01/2010
The formula is PV/T = PV/T where on the left side... sure you turn 60 degrees celsius into Kelvins ( stp is 760 torr and 273 Kelvins) it looks like this...
2 Answers · Science & Mathematics · 03/12/2011
STP means standard temperature and Pressure, which is 1 atm and 273K (0 degrees C...08206 Latm/molK) (273 K) V = 28.25 L and for the second one you use a formula derived form PV=nRT because D = m/V and n = m/MM (MM is molar...
4 Answers · Science & Mathematics · 14/03/2010
You need to use the ideal gas formula . PV=nRT Substitute for n the mass over the molar mass, then solve for the volume using STP . The mass of the gas over the volume will yield the density.
1 Answers · Science & Mathematics · 09/01/2013
Always remember this formula : P(pressure) x V(volume) = n(number of moles) x R...
2 Answers · Science & Mathematics · 04/04/2011
