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... NO2. This has a formula mass of 46 g/mol At

**STP**, 1 mol of any gas occupies a volume of 22.4 L. So, 0.974...1 Answers · Science & Mathematics · 17/10/2020

...on what you have been taught is the molar volume of a gas at

**STP**(which depends on what you were taught are the standard...1 Answers · Science & Mathematics · 08/08/2020

(3.17 g/L) / (22.4 L/mol) = 71.008 g/mol The common gas with a molar mass like that is chlorine (Cl2).

2 Answers · Science & Mathematics · 27/11/2019

P4(s) + 12 HCl(aq) → 4 PH3(g) + 6 Cl2(g) (20.0 g P4) / (123.895 g P4/mol) = 0.161427 mol P4 (5.000 L) x (7.225 mol HCl/L) = 36.125 mol HCl 0.161427 mole of P4 would react completely with 0.161427 x (12/1) = 1.937124 moles of...

2 Answers · Science & Mathematics · 29/07/2019

I'd set it up like this .. 704L H2O @

**STP**.. .... 1 mol H2O.. ... . ... .. . 2 mol NH3.. .. .. 17.04g NH3...2 Answers · Science & Mathematics · 29/07/2019

P1 / T1 = P2 / T2 Be sure to convert deg C to K for gas problems. P1 * V1 / T1 = P2 * V2 / T2 same warning as above. You get to do the math.

1 Answers · Science & Mathematics · 07/07/2019

Gas solution.... H2 and N2 don't react at

**STP**, so all you have is a mixture. The substance in greater amount...2 Answers · Science & Mathematics · 02/07/2019

... / T2 ............. P2, V2 and T2 are at

**STP**P2 = P1V1T2 / (T1P2) V2 = 726 torr x 15.5 mL...2 Answers · Science & Mathematics · 30/05/2019

... = 6.23 mol we must assume some T and P If it is

**STP**then V = 6.23 mol * 22.4 l/mol = 139.5 L round appropriately When...3 Answers · Science & Mathematics · 24/05/2019

Part a) the steps are correct, but I get 0.334 moles of H2 and a volume of 7.48 L, or 7.5 L after rounding to two sig-figs. For part b), I get 1.645 atm, or 1.6 rounded to two sig-figs.

1 Answers · Science & Mathematics · 04/05/2019

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