1...At

**STP**, 1.0mol of gas occupies 22.4 L. So, 16.3 moles = 16...2 Answers · Science & Mathematics · 06/05/2010

1. What is the mass of a sample of oxygen gas if its volume at

**STP**is 22.4 L? at**STP**, 22.4L is the volume of 1...1 Answers · Science & Mathematics · 24/08/2011

v = 792mL = 0.792L molar volume (VM) at

**STP**= 22.4 L number of moles (n) = v / VM = 0.792 / 22...3 Answers · Science & Mathematics · 11/12/2008

**STP**= standard Temperature and pressure This is T = 0 deg Celcius (273.15 K) and P = 1.0 atm At**STP**1 mole of any ideal gas has a volume of 22.4 L. So ...4 Answers · Science & Mathematics · 26/09/2009

One mole of ANY gas at

**STP**has a volume of 22.4 L. 545 mL He x (1 L / 1000 L) x (1 mole He / 22.4 L He) x (4.00 g He / 1 mole He) = 0.0973 g He1 Answers · Science & Mathematics · 28/06/2013

**STP**is an acronym for standard temperature and pressure. Standard Temperature = 273 Kelvin= 0 degrees Celcius Standard Pressure = 1 atm= 760 torr= 760 mmHg1 Answers · Science & Mathematics · 12/02/2014

**STP**means standard temperature and Pressure, which is 1 atm and ...4 Answers · Science & Mathematics · 14/03/2010

...806 : x x = moles SO2 produced = 0.586 Volume at

**STP**= 0.586 x 22.4 =13.1 L2 Answers · Science & Mathematics · 13/12/2009

The

**STP**is already a defined set of conditions (273 K and 1.0 L). It doesn't change. So the**STP**using H2 is the same as when H2SO4 is used.1 Answers · Science & Mathematics · 19/11/2010

V= nRT / P

**STP**= 0c = 273 k andd 101.325 kpa V = 8.0 mols x 8.31 kpa * L / mol * K x 273 k / 101.325 kpa v= 179.11 L v= 179L ans = 62 Answers · Science & Mathematics · 29/01/2011