...°f(reactants)) ∆G°f (Ni) = 0 element in its standard state. ∆G(rxn) = [∆G°f(Ni(CO)4)] - [4∆G°f...

1 Answers · Science & Mathematics · 03/07/2011

...between them is the same. Remember that

**temperature**is a measurement of the average molecular kinetic energy of...affect how quickly it effuses) (B), (C),**and**(E) can be all be eliminated as well since...1 Answers · Science & Mathematics · 22/04/2012

...way of keeping measurements of

**temperature and pressure**constant so that when different formulas ...part of it's calculation relates volume,**pressure**,**temperature and**moles of a gas under 1 set of known...3 Answers · Science & Mathematics · 23/11/2008

...two different values for this: -175

**and**-275...Check it) Now,**standard**enthalpies of formation are based on 298 K for the**temperature and**1 atmosphere of**pressure**(you might use Pa or kPa for the**pressure**--different texts**and**...1 Answers · Science & Mathematics · 02/03/2014

.... Since you know the change in

**temperature**(T - T0 = 2T0), you can... the heat capacity at constant volume,**and**the appropriate equation. You would use...law,**and**see what happens at constant**pressure**.1 Answers · Science & Mathematics · 02/12/2013

for pressure 1 atm or 760 mm Hg or torr (mercury millimeters) and 25°C or 298.15 K as 0 K = −273.15 °C and 273.16 K = 0.01 °C.

2 Answers · Science & Mathematics · 09/03/2012

... Dalton's Law of Partial Pressures , the

**pressure**of oxygen without water vapor is (740 - 22.4) torr. You will need to look up STP to ascertain the correct value for the**temperature**, but I believe it is 273 K. Since P1 * V1...3 Answers · Science & Mathematics · 13/10/2007

standard temperature is 0 ℃. standard pressure ; 101.325 kPa, 1.00 atm, 760.0 mmHg

2 Answers · Science & Mathematics · 16/06/2011

...25 hPa ; T25 = 298,15 K (25 °C) (Conditions standard de température et de pression) ► ρ25 = 1,184 kg/m3. ρ = 1,184 kg/(1E6 cm³...

1 Answers · Science & Mathematics · 07/07/2011

...2, T must double. Remember that you are doubling the

**temperature**in Kelvin, not Celcius. The new**temperature**would be 546.3...2 Answers · Science & Mathematics · 04/06/2009