Yahoo Web Search

  1. There are several recognized standards for pressure and temperature ratings. These typically cover flanges and indirectly valves...

    1 Answers · Science & Mathematics · 08/11/2008

  2. ... = 20% H mass of C in the sample = 1.34 - .2678 = 1.0722 g and 1.0722 / 1.34 % C = 80 % C moles of gas = PV / Rt...

    1 Answers · Science & Mathematics · 24/11/2012

  3. At 20 °C and 101.325 kPa, dry air has a density of 1.2041 kg/m3. Volume=8*6*4=192m3 density = mass / volume mass = density*volume mass=1.2041*192 mass =231.1872 kg

    4 Answers · Science & Mathematics · 10/05/2009

  4. You can take your pick. The US Bureau of Standards says 760 mm Hg and 20 degrees Celsius. The International ...

    3 Answers · Science & Mathematics · 13/11/2009

  5. ...=T If T increases and P remains the same, then V has...remain constant. The same goes for P, if the pressure increases, the T has to increase. 1...

    2 Answers · Science & Mathematics · 25/01/2010

  6. .... Using the " Standard Atmosphere Calculator...source, I get @20,600 m Temperature - 217.250 K Pressure - 4981.29 Pa Density...

    1 Answers · Science & Mathematics · 08/11/2013

  7. ...common standard is 20 °C (293.15 K, 68 °F) STP ( Standard Pressure and Temperature ), from wikipedia: In chemistry, standard condition for temperature and pressure (informally...

    1 Answers · Science & Mathematics · 02/01/2011

  8. STD stands for Standard Temperature and Pressure Standard Temperature is typically 60 deg F Standard ...

    3 Answers · Science & Mathematics · 09/02/2012

  9. 44.8 l is 2 moles of gas. One mole of diatomic nitrogen gas (N2) would mass 28 g. Twice that is 56 g. Seems to me the answer ought to be (B).

    1 Answers · Science & Mathematics · 02/04/2010

  10. ...you just have to look up any thermodynamic table on that gas/liquid. http://www.astm.org/ Standards /D4651.htm I would think any working fluid used would be used at a temperature very close to it's critical temperature so that it's thermodynamic potential could be...

    1 Answers · Science & Mathematics · 02/02/2012

  1. Try asking your question on Yahoo Answers