...to moles using 16gm = 1.0 mole of methane gas, b) Enter the

**temperature**in K, the**pressure**, c) enter the ideal gas constant,**and**d) solve for V.2 Answers · Science & Mathematics · 20/10/2008

...only at STP. Using PV = nRT is the general solution

**and**works with any values of T**and**P.2 Answers · Science & Mathematics · 30/08/2013

moles C2H2 = 8.50 g/ 26.038 g/mol=0.326 there are two ways : 1) V = nRT / p = 0.326 x 0.08206 x 273 K / 1 atm =7.30 L 2) at STP one mole of any gas occupies 22.4 L V = 22.4 x 0.326 = 7.30 L

1 Answers · Science & Mathematics · 30/01/2010

P1 * V1 / T1 = P2 * V2 / T2

3 Answers · Science & Mathematics · 22/02/2014

SATP is

**standard**ambient**temperature and pressure**which is 25 deg celcius (298.15 Kelvin)**and**100.0 ...1 Answers · Science & Mathematics · 23/09/2012

STP (

**Standard temperature and pressure**) is IUPAC defined to be 0°C... are correct. Note that despite temperature being specified for SATP in ...1 Answers · Science & Mathematics · 24/09/2012

STP ..... STP is "

**standard temperature and pressure**", or 1.00 atm**and**0C (273.15K). One mole of any ideal gas...1 Answers · Science & Mathematics · 12/04/2018

**Standard Temperature and Pressure Standard Temperature**= 273K= 0C= 32F**Standard**...5 Answers · Science & Mathematics · 09/08/2012

At

**standard temperature and pressure**, the volume of one mole of a gas is 22.4 liters...gas that has a density of 2.18 g/L at 66°C and 720 mm Hg. Density = mass ÷ volume Let’s...2 Answers · Science & Mathematics · 08/05/2017

Convert to

**standard**conditions volume = 1.00 x 273/294 x 717/760 L Let's...1 Answers · Science & Mathematics · 05/10/2012