Yahoo Web Search

  1. Δ = Δ° + RT ln P(CH4)^2 / P(C2H6) P(H2) Δ = -72.6 kJ/mol + 8.314 J/molK (298K) ln (0.850)^2 / (0.200)(0.450) Δ = -67.4 kJ/mol

    1 Answers · Science & Mathematics · 13/10/2020

  2. ...) = 4.07² × 5.42² / (4.80³ × 5.25⁴) = 0.00579 Standard change in Gibbs free energy, ΔG° = -R T ln(Kp...

    1 Answers · Science & Mathematics · 11/11/2020

  3. ... = ((6.05 g H2O) / (18.01532 g H2O/mol)) x (0.082057366 L atm /K mol) x (215.77 + 273.15) K / (0.838 L) = 16.078 atm H2O...

    2 Answers · Science & Mathematics · 27/01/2021

  4. ... defined as 1 atm pressure and 273.15 K. Under.../mol.  More recently, the standard conditions have been...still commonly taught, at least in the US. So, I...

    1 Answers · Science & Mathematics · 08/08/2020

  5. ... right up to the point of balancing the reaction. So, in the cell, Al(s) is being oxidized to Al3+ and...

    1 Answers · Science & Mathematics · 19/08/2020

  1. Try asking your question on Yahoo Answers