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  1. You are right, but in this case, you are asked to find the temperature at " standard pressure ", not standard "temperature and... / nR P = 1 atm V = 2.00 L (from ...

    2 Answers · Science & Mathematics · 22/10/2009

  2. p = density of water = 1g/mL = 1000kg/L 1 atm = 101.3 kPa = 101.3kN/m^2 Pressure = pgAh/A >(Ah is volume, pAh is mass...

    2 Answers · Science & Mathematics · 10/03/2009

  3. This is about correlation. 1 ATM and 0 is the standard to get one mole. 22.4 L = volume of 1.... If you added enough hot air in a short period of time, it would pop, the volume would...

    1 Answers · Science & Mathematics · 26/05/2012

  4. ... <-------------- I use the equivalents to 1.000 standard atmosphere of pressure at sea level, PE0. PE0 = 1.000 atm = 101.325 kPa = 760 mm Hg = 760 torr = 14.697 psi

    3 Answers · Science & Mathematics · 02/06/2014

  5. Calculate the number of moles in 25.0 g of oxygen. 25g/32g= .781 mol Next plug the equation in PV=nRT 1 atm x 1.5 L=.781 mol x .0821 x T T= 23.4 K

    1 Answers · Science & Mathematics · 03/07/2013

  6. at STP( standard temperature and pressure ) ie T=273K , P= 1.013 X 10^5, 1 mole of a gas ...

    1 Answers · Science & Mathematics · 14/12/2008

  7. std conditions are 1 atm and 273K (0C) normal conditions? usually close to 1atm temperature ~ 25C or close to 300K

    1 Answers · Science & Mathematics · 08/09/2010

  8. ...gas is calculated as though said gas were the only one in the given volume. STP: 273 K (0 C) & 1 atm (1.013 x 10^5 Pa) PV = nRT, where P = pressure , V = volume, n = number of moles, R = ideal gas constant...

    1 Answers · Science & Mathematics · 11/12/2012

  9. ...correct units. P = 1.3 atm (convert to kPA using http://www.unitconversion.org/ pressure / standard -atmospheres-to-...believe) So substitute these in , find n, then multiply the molar mass...

    4 Answers · Science & Mathematics · 19/11/2011

  10. 11.2 L at STP holds 0.5 moles of atoms. 3.011 x 10^23 atoms is the answer (this is 0.5 of Avogadro's Number).

    2 Answers · Science & Mathematics · 05/08/2011

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