Yahoo Web Search

  1. ...temperature and pressure . Standard temperature is 0°C or 273 K. Standard pressure is 1 atm or 101.3 kPa or 760 mmHg. Note: The volume of one...

    5 Answers · Science & Mathematics · 14/07/2008

  2. PV=nRT Standard Temperature = 0 C = 273.15 K P=nRT/V = (0.932)(0.082057)(273.15)/46.7=0.447 atmospheres

    1 Answers · Science & Mathematics · 11/05/2009

  3. Standard Pressure is 1 atm . Since it's not in the choices, find an equivalent of 1 atm . 1 atm = 760 torr = 760 mm Hg = 101325 Pa .: C. 101325 Pa

    7 Answers · Science & Mathematics · 16/07/2009

  4. ..., 760 mmHg is equal to 1 atm , which is standard pressure , so I would just multiply each question's... of COv2 (g) 5(760)-5(720)= difference in pressure This may or may not be a feasible...

    2 Answers · Science & Mathematics · 07/11/2011

  5. ... area is: A = π*D^2/4 = .0515 m^2 A standard atmosphere is 101.325 kPa = 101.325 kN/m^2 The pressure is: 16.8*101.325*10^3 = 1.702*10^6 N/m^2 The maximum lift...

    2 Answers · Science & Mathematics · 13/11/2009

  6. ... standard temp (273 degrees Kelvin), and standard pressure (1 atm ). Use this equation: Pressure * .... Than times that by the 2 in Cl2 to find the total moles of Cl2...

    1 Answers · Science & Mathematics · 30/01/2012

  7. ... will help you with conversions. If you type "1 atm in kPa" into the search bar and press Enter, it will give you the answer...

    2 Answers · Science & Mathematics · 17/10/2013

  8. yep except I would have written it: 350 ml * 740 torr/760torr but same answer

    1 Answers · Science & Mathematics · 19/04/2011

  9. The standard equation for finding the ...same so 1.16 x 15 / 296.5( T in Kelvin) = X x 12.5 / 291.7. solve to find your new pressure in ATM is 1.369465 Correct...

    3 Answers · Science & Mathematics · 29/08/2011

  10. ... no repulsion between electrons unless they come close to each other in a certain proximity. The gravity pressure of space on a electron is equal to the mass of the electron times the...

    4 Answers · Science & Mathematics · 07/04/2011

  1. Try asking your question on Yahoo Answers