...pipe equals the atmospheric. Let's assume that ist is equal to standard atmospheric pressure : pₐ = 1 atm = 101,325 Pa (a) In inviscid flow there is no pressure loss due to friction Therefore the pressure ...

1 Answers · Science & Mathematics · 08/07/2011

Assuming STP (

**Standard**Temperature and**Pressure**) T = 25oC = 25+273 = 298K and p = 1**atm**= 1.103x10^5Pa We can calculate the number of moles...2 Answers · Science & Mathematics · 26/12/2009

The unit of measurement called standard atmosphere ( atm ) is defined as 101.325 kPa... .85atm, multiply by that = 86,126Pa Pressure = F/area = N/m² F...

1 Answers · Science & Mathematics · 09/09/2016

...the internal

**pressure**(PV=mRT or**in**other words**Pressure**times Volume is equal to... ) 9.psi, mmHg, kPa,**atm**17. refer yourself back to (PV...1 Answers · Science & Mathematics · 19/08/2012

a) (8.56 + 14.7) = 23.26psia. b) (10 + 1) = 11

**atm**. absolute.1 Answers · Science & Mathematics · 28/11/2010

I assume that

**in**this question 'system' mean...39;gas'. The total**pressure**of the gas is the sum...at 35C. The**standard**atmospheric**pressure**is 101.3kPa, so 0.493**atm**corresponds to 49...1 Answers · Science & Mathematics · 29/04/2012

...oil P = 0.7 * 9.8 * 1.02 = 6.997 kPa 1 atmosphère [ atm , standard ] = 101325,01 pascal 8.33 kPa =, 8330 Pa 6.997 kPa = 6997 Pa absolute pressure at the bottom of the container = 101325 + 8330 + 6997 = 116652 Pa http://...

1 Answers · Science & Mathematics · 10/03/2013

... * 1kg / 2.2lb = 548 N 0.59in² * (0.0254m/ in )² = 0.0003806 m² (i) p = 548N / 0....ii) p = 1.44e6Pa * 1atm / 1.013e5Pa = 14.2 atm (iii) 123lb / 0.59in² = 208 psi Hope this ...

1 Answers · Science & Mathematics · 04/04/2017

... is 0 degrees Celcius (273.15 Kelvin) and the

**standard Pressure**is 1**atm**. = 760 mm Hg. (Yea, yea, IUPAC**in**1982 said 1bar should replace 1**atm**...see if your textbook took...6 Answers · Science & Mathematics · 23/05/2008

1) Calculate the volume of 1 mol of gas

**in**the scuba tank. Under**standard**conditions (1atm, 0 C) 1 mol of...=nRT we deduce that at 20 C, 12**atm**1 mol gas has a volume of 22.4* (293/273...1 Answers · Science & Mathematics · 07/12/2006