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  1. centripetal acceleration a = v²/r = (7m/ s )² / 1.5m = 32.7 m/s² a) T = m*√(a² + g²...

    1 Answers · Science & Mathematics · 29/10/2020

  2. (a) Determine the magnitude of the block' s weight that is directed down the ramp in Newtons. Fx...

    1 Answers · Science & Mathematics · 29/10/2020

  3. ... + y²) = 739 N ◄ correct Θ = arctan(y/x) = 48º S of W ◄ correct! or 42º W of South

    1 Answers · Science & Mathematics · 29/10/2020

  4. ...9.6) = 49° Acceleration: a = Fres/m a = 9.6 / 27.1 = 0.35 m/ s ^2

    1 Answers · Science & Mathematics · 29/10/2020

  5. ...at the launch, v² = 2gh = 2 * 9.8m/s² * (100 - 10)m = 1764 m²/ s and then the trajectory equation gives y = h + xtanΘ - gx² / (...

    1 Answers · Science & Mathematics · 29/10/2020

  6. M = 13.5g , g = 9.8m/ s ^2 Weight W = g = 13.5×9.8 = 132.3N

    1 Answers · Science & Mathematics · 28/10/2020

  7. ...81*27.0² / (2v²cos²38.0º) solves to v = 17.6 m/ s Hope this helps!

    1 Answers · Science & Mathematics · 29/10/2020

  8. ... = Vi + a*t so t = (Vf- Vi)/a = (0 - 36)/(-108) = 1/3 s <<<<<...

    1 Answers · Science & Mathematics · 28/10/2020

  9. Because these vectors are perpendicular, we can just use Pythagoras: 1. v = √(230² + 55²) km/h = 236 km/h 2. Θ = arctan(55/230) = 13º E of North

    2 Answers · Science & Mathematics · 28/10/2020

  10. Change in PE = mgh = (0.0065 kg)(9.8 m/s²)(14 m) = 0.892 J  ( with 3 sig fig) Spring PE = change in gravitational PE ½kx² = 0.892 k = 2(0.892)/x² k = 2(0.892)/(0.09)² k = 220 N/m

    1 Answers · Science & Mathematics · 28/10/2020

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