vx = r*cosθ vx = (1410 km/h)cos45° vx = 997 km/h

1 Answers · Science & Mathematics · 02/04/2010

SQRT (6^2 + 8^2) = 10 N, 8 deg South of East

1 Answers · Science & Mathematics · 18/12/2012

The

**southwest**portion of the walk is the hypotenuse of an isosceles right triangle (isosceles because...1 Answers · Science & Mathematics · 17/05/2016

...north, so V = (0, 150) Second is just a little harder -

**southwest**is at a 45° angle down and to the left. So both X and ...1 Answers · Science & Mathematics · 30/10/2012

Your 1st answer is correct, but it should be

**southwest**instead of southeast 2a). You'll use Pythagoras again, but I...1 Answers · Science & Mathematics · 10/02/2013

..., he had gone only 30km, and was headed

**southwest**(45º clockwise from his intended direction). Draw that vector...1 Answers · Science & Mathematics · 15/04/2012

...northeast. That means that the wind vector is pointed to the

**southwest**. Break down your diagonal vector into 2 separate vectors: 1 vertical...3 Answers · Science & Mathematics · 25/06/2013

...travel cancel one another. You end up with a vector which points somewhat

**southwest**of where you started. You need to use geometry to find the length of that...1 Answers · Science & Mathematics · 26/03/2016

...of - atan(.219/.321) = - 145.7° relative to east or a true course of 235.7° (roughly west

**southwest**)1 Answers · Science & Mathematics · 26/09/2009

Using F.Viete theorem : d = √125^2+65^2-2*65*125*cos135° = 177 km Θ = arccos(65/(125*√2)) = 1.19 radians (68.36°) with respect to south

3 Answers · Science & Mathematics · 18/09/2013