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1: area of a

**sector**=90/360xπ(r^2) 4π=0.25π(r^2) cut out π 4/0.25=r^2 taking square root on both sides: r=4 so the answer is 4cm. 2: area of a**sector**=90/360xπ(r^2) 9/8πcm^2=45/360π(r^2) following the same procedure as...2 Answers · Science & Mathematics · 11/01/2013

Hi,

**Sector**AOB has a 120 degree angle so is 1/3 of the circle. Its...2 Answers · Science & Mathematics · 06/08/2013

Imagine the

**sector**in the x-y plane with radius R and let alpha be its angle. Suppose...where x = R - r. The line from the center perpendicular to a side of the**sector**creates a right triangle, showing that x sin(alpha/2) = r. ...1 Answers · Science & Mathematics · 10/04/2008

The perimeter of the

**sector**given the angle to be 30° and radius 5 inches: 10 pi / 12 + 10 = 12.617993877991495 inches6 Answers · Science & Mathematics · 04/04/2020

**sector**x radian area = (r^2 x)/2 arc length = r x they are not propotional because Area / arc length = r/2 , (it's not a constant)1 Answers · Science & Mathematics · 15/04/2015

A

**sector**is formed by two radii of a circle and the arc the two ...central angle is x and the radii are each r,the are of**sector**is simply area of entire circle times x/360, if angle is in ...2 Answers · Science & Mathematics · 19/05/2011

... the two straight sides bordering the

**sector**are tangent to the circle, we know that the right triangle...4*csc(40) + 4 = 4*(1 + csc(40)) cm. The area of the**sector**is therefore (1/2)*r^2*(theta) = (1/2)*[4*(1 + csc(40...5 Answers · Science & Mathematics · 08/01/2014

**Sector**angle ,θ= 30° =π×30°/180° = π/6 radians Radius, R= 15 cm Area A= (1/2)R²θ where θ is in radians Hence A= (1/2)×15²× π/6 =58.90 cm²2 Answers · Science & Mathematics · 27/02/2017

The area of

**sector**is equal to the degree(70) over 360 degrees, multiples by pi...3 Answers · Science & Mathematics · 20/03/2013

**Sector**angle ,θ= 30° =π×30°/180° = π/6 radians Radius, R= 15 cm Area A= (1/2)R²θ where θ is in radians Hence A= (1/2)×15²× π/6 =58.90 cm²4 Answers · Science & Mathematics · 12/07/2013

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