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**sector**) = ½θr², where: • r is the**sector**radius • θ is the**sector**'s central angle (in radians) OR... A(**sector**) = θ/360(πr²), where: • r is the**sector**radius • θ is the...1 Answers · Science & Mathematics · 14/12/2011

area of

**sector**=(180*square of radius)/angle of**sector**in radians circumference=(360*radius)/angle of**sector**in radians5 Answers · Science & Mathematics · 20/12/2008

The area of a

**sector**given the radius of the circle (r) and the angle that subtends the**sector**...3 Answers · Science & Mathematics · 29/08/2010

Draw a circle. Show i)

**Sector**containing angle theta, and label the radius 8 ii...circumference= 14/16(pi), or 7/(8pi) The area of the**sector**is thus 7/(8pi) of 64(pi) 7/(8pi) / 64pi =7/8pi...1 Answers · Science & Mathematics · 27/04/2009

... area is found by (pi).r^2 The desired

**sector**sweeps 1.8 radians of a 2pi radians area, or (1.8)/(2pi...2 Answers · Science & Mathematics · 30/03/2014

Divide the

**sector**into a large number of parts so that each part is close to an...to the arc length and height equal to the radius of the circular**sector**. => area of the**sector**= (1/2) r * (sum of lengths of all arcs) = (1/2) r * rθ, where θ...2 Answers · Science & Mathematics · 06/01/2009

Formula for area of

**sector**is: area of**sector**/ area of circle = angle of**sector**/ 360 (which is angle...4 Answers · Science & Mathematics · 07/02/2010

...to solve this. the area of the circle is pi*r^2 and that the area of the

**sector**is its angle measure divided by 360 times the area of...5 Answers · Science & Mathematics · 06/10/2011

**Sector**arc-length = 20 cm radius, r = 10 cm Area of the**sector**= pi(r^2)*20 / 2pi*r Area = 10*r = 10*10 = 100 sq.cm >==========< ANSWER1 Answers · Science & Mathematics · 03/08/2011

Public

**sector**comprises of companies or enterprises that are run...1 Answers · Science & Mathematics · 27/02/2017

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