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**sec**^2x/tan^2x you're right tan^2x+1 / tan^2x use partial fraction tan^2 x / tan^2... could also express the given in sin and cos**sec**^2x/tan^2x (1/cos^2 x) / [(sin^2 x)/cos^2 x] get the reciprocal of the denominator and...2 Answers · Science & Mathematics · 06/05/2013

d(

**sec**²(x)) = 2**sec**(x)d(**sec**(x)) = 2**sec**(x)[tan(x)**sec**(x)]dx = 2**sec**²(x)tan(x) dx The power rule... the function (2**sec**(x)) multiplied by the differential of the function, d(**sec**(x)). Since the function is a function of x, the chain rule multiplies...4 Answers · Science & Mathematics · 09/10/2015

The

**SEC**is clearly the best conference in college football from top to bottom. ...to be overrated). Yes, the Pac-10 isn't as good as the**SEC**, but I wouldn't rank it any lower than #2 in terms of conference...7 Answers · Sports · 20/08/2007

Remember that

**sec**x = 1/(cos x), so multiply both sides of the original by cos x and you get: 1...2 cos x Multiply by**sec**x instead and you get:**sec**² x + 1 = 2**sec**x Those give you a way to reduce squares of cos x or**sec**x for...2 Answers · Science & Mathematics · 09/08/2015

**sec**^2(x) = 2sec(x)*tan(x)**sec**(x)**sec**^2(x)tan(x) =**sec**^2(x)***sec**^2(x) + tan(x)*2sec(x)tan(x)**sec**(x) the first one is just the chain rule.. the second is the product rule.1 Answers · Education & Reference · 19/05/2008

No. The

**SEC**has not embarrassed itself. Except for LSU.... It never ceases to amaze me the number of**SEC**haters that pop up on various boards or posters who claim the...15 Answers · Sports · 08/01/2010

d/dx

**sec**(x) =**sec**(x) tan(x) is correct. Also, d/dx tan(x) =**sec**²(x). Now use the product rule to find d/dx**sec**(x) tan(x): d/dx**sec**(x) tan(x) =**sec**(x)**sec**²(x) + tan(x) (**sec**(x) tan(x...1 Answers · Education & Reference · 15/11/2011

∫ 36x²

**sec**^4(x³) dx = rewrite it as: ∫ 12**sec**^4(x³) 3x² dx = let...d(x³) = du 3x² dx = du thus, substituting: ∫ 12**sec**^4(x³) 3x² dx = ∫ 12**sec**^4(u) du = pull the constant out and rewrite...2 Answers · Science & Mathematics · 23/02/2010

**sec**θ = 1 / cos θ In quadrant 1 all ratios are positive Now cos θ = sin [(π/2) - θ] so**sec**θ = 1 / sin [(π/2) - θ]1 Answers · Education & Reference · 09/12/2012

**SEC**is the strongest conference in the NCAA. Of course this...11 Answers · Sports · 10/09/2007

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