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  1. [tan(t) + sec (t) - 1] / [tan(t) - sec (t) + 1] = tan(t) + sec (t...left hand side (LHS). LHS = [tan(t) + sec (t) - 1] / [tan(t) - sec (t) + 1] Change everything...t) By definition, LHS = tan(t) + sec (t) = RHS

    1 Answers · Science & Mathematics · 02/03/2007

  2. sec (x) - sin(x) = [tan^2(x) + cos^2(x)] / [ sec (x) + sin(x)] LS: sec (x) - sin(x) = [ sec (x) - sin...x) = 1 dividing through by cos^2(x) tan^2(x) + 1 = sec ^2(x) tan^2(x) = sec ^2(x) - 1 resubstituting tan^2(x): = sec ...

    2 Answers · Science & Mathematics · 30/11/2009

  3. x * tan(x) * dx / ( sec (x) + tan(x)) => x * tan(x) * ( sec (x) - tan(x)) * dx / ( sec (x)^2 - tan(x)^2) => x * (tan(x) * sec (x) - tan(x)^2) * dx / 1 => x * ( sec (x) * tan(x) - sec (x)^2 + 1) * dx u = x du = dx dv = sec (x) * tan(x) * dx - sec (x...

    3 Answers · Science & Mathematics · 29/04/2013

  4. sec [(5/2)x] tan[(5/2)x] dx = (I assume x is in the numerator) let [(5/2)x] = u → x = (2/5)u → dx = (2/5) du then, substituting, you get: ∫ sec (5/2x) tan(5/2x) dx = ∫ sec u tan u (2/5) du = take out the constant: (2/5) ∫ sec ...

    3 Answers · Science & Mathematics · 14/08/2008

  5. y* sec (x) = x*tan(y) Differentiating both sides with respect to x, y * d/dy( sec (x)) + sec (x) * dy/dy = x * d/dy(tany) + tan(y) * dx/dy Or y * d/dy( sec (x...

    2 Answers · Science & Mathematics · 18/07/2009

  6. The SEC has only lost 1 BCS game since 2001. By contrast, Choke...also blistered the ACC champion by 41 points. The SEC 's bowl record is more impressive when considering they play few ...

    18 Answers · Sports · 03/01/2008

  7. 1+ sec (x)=tan(x) 1+ sec (x)=sin(x)/cos(x) Crossing multiplication. cos(x)(1+ sec (x))=sin(x) (cos(x)+1)^2=(sin(x))^2 cos^2(x)+2cos(x)+1=sin^2(x) ..... ... ...

    11 Answers · Science & Mathematics · 02/08/2013

  8. First, a few identities: [a] sec x = 1 / cos x [b] csc x = 1 / sin x [c] cos x + n360 = cos x...90. 5) Apply [i], [j] or [k] if possible. So... sec -150 = 1/cos -150 [a] = 1/cos 150 [e] = -(1/cos 30) [g] = -(1...

    1 Answers · Science & Mathematics · 03/12/2007

  9. sec (√x) / √x dx let √x =t (1(/2√x))*dx=dt substitute ∫ sec (√x) / √x dx=∫ 2sect dt =2ln|sect+tant|+C t=√x hence ∫ sec (√x) / √x dx...

    2 Answers · Science & Mathematics · 22/06/2013

  10. sec ^2(18) - tan^2(18) First off, remember that there is an identity that relates sec ^2(x) with tan^2(x); it goes sec ^2(x) = tan^2(x) + 1. Therefore...

    6 Answers · Science & Mathematics · 13/03/2007

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