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**SEC**team has never lost to a non**SEC**team. Lets see last year...on and on. I could look up their whole standings versus non**SEC**opponents, but I dont have the time. Look at their...7 Answers · Sports · 02/10/2007

...answerer had right idea, but wrong answers...

**sec**= 1 / cos 1) if**sec**= -2/sqrt(3), then cos = -sqrt(3) / 2 arc...**sec**= -sqrt(2), then cos = -1/sqrt(2) = -sqrt(2) / 2 arc**sec**(-sqrt(2)) = arc cos (-sqrt(2) / 2) = 135 (this is a 45...2 Answers · Science & Mathematics · 07/07/2008

**sec**(x) = 1/(cos(x)) let y = 1/(cos(x)) d/dx 1/cos(x) = by the quotient rule y'...sin(x)(1)]/cos^2(x) = sin(x)/cos^2(x) =[sin(x)/(cos(x)][1/cos(x)] = tan(x)**sec**(x) To find the second derivative do quotient rule of sin(x)/cos^2(x...5 Answers · Science & Mathematics · 04/12/2011

**SEC**refs have only two purposes: 1. To make sure an**SEC**team plays for the N.C. 2. To make sure the**SEC**gets a second BCS Bowl.4 Answers · Sports · 29/10/2009

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**sec**θ)/(1+ (**sec**θ)) = (1 - cos θ)/(sin²θ) recall (**sec**θ) = 1/(cos θ), thus [1/(cos θ)]/[(1+ 1/(cos θ))] = (1 - cos θ)/(sin²θ...2 Answers · Science & Mathematics · 17/04/2013

LMAO.. The

**SEC**fans are shameless. A couple of years ago after ... after the Cal game Tennessee then went on to the**SEC**title game. ROFLMMFAO!!!! Hicks...16 Answers · Sports · 02/09/2008

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**sec**^4(x/2) dx Let, u = x/2 du = 1/2 dx 2du = dx 2 ∫**sec**^4u du 2 ∫**sec**^2u * (1+tan^2u) du Let, v = tanu dv =**sec**^2u du 2...2 Answers · Science & Mathematics · 07/11/2010

Given:

**sec**x = -1.5 = -3 / 2 Remember**sec**x = 1 / cos x = 1 / (adjacent / hypotenuse...that sin = opposite / hypotenuse. sin x = (√5 / 3) Remember that cos x = 1 /**sec**x. cos x = 1 / (-3 / 2) = (-2 / 3) Remember that tan = sin / cos. tan x...1 Answers · Science & Mathematics · 29/09/2010

**SEC**Rules! Why, 7-2 in bowl games this year, back to back national..., every game is watchable while the big ten isn't at all, no team in the**SEC**lost to a Division 1AA team while over ranked at #5 ...13 Answers · Sports · 08/01/2008

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**sec**(t/3) dt When you said to let u = t/3 you were correct...should get this: u = t/3 du = 1/3 dt Rewrite with u's: (1/3) ∫**sec**(u) du (1/3)ln|**sec**(u) + tan(u)| + C Plug back in t's: (1/3...1 Answers · Science & Mathematics · 02/03/2010

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