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  1. sec (b)csc(b) = 2csc(b) sec (b)csc(b) - 2csc(b) = 0 csc(b) * ( sec (b) - 2) = 0 csc(b) = 0 1/sin(b...5pi/3 + 2pi * k b = (pi/3) * (1 + 6k) , (pi/3) * (5 + 6k) tan(t) + sec (t) = 1 sin(t)/cos(t) + 1/cos(t) = 1 (sin(t) + 1) / cos(t) = 1 sin(t...

    5 Answers · Science & Mathematics · 05/04/2012

  2. sec (x/2)dx Multiply numerator and denominator by ( sec (x/2)+tan(x/2) and get ∫ sec (x/2)dx= ∫{ sec (x/2)( sec (x...x/2)tan(x/2)} dx= dt i.e dx =2dt/{ sec²(x/2) + sec (x/2)tan(x/2)} Subsituting ∫{sec²(x...

    5 Answers · Science & Mathematics · 09/03/2011

  3. sec ^4 x dx = ∫ sec ^2 x sec ^2 x dx Integrate by parts dv= sec ^2 x dx; v = tan x; u = sec ^2 x ; du = 2 sec ^2 x tan x ∫ u dv = u v - ∫ v du...

    3 Answers · Science & Mathematics · 11/03/2014

  4. Separate the integral to sec (4x) tan (4x) since the derivative of sec x is sec x tan x, we'll need this...change tan^2 into sec ^2 - 1 (trigonometry identity) Integral (( sec (4x) tan (4x) sec ^2 (4x) ( sec ^2 (4x) - 1) dx) Use u substitute for sec (4x). Derivative...

    3 Answers · Science & Mathematics · 04/12/2011

  5. To remember sec -butyl, I always find it helpful to remember what the " sec " actually ...secondary carbon atoms (attached to two other carbons). The sec -butyl group is attached to the parent molecule via one of these " sec ...

    6 Answers · Science & Mathematics · 07/07/2010

  6. y = sec (8^x) tan [ (1+e^x) /(1-e^x)] Apply the product rule: dy/dx = d/dx sec (8^x) tan [ (1+e^x) /(1-e^x)] + sec (8^x) d/dx... (3) into (2) d/dx tan [ (1+e^x)/(1-e^x)] = sec ^2 [ (1+e^x)/(1-e^x)] times -2e^(2x) / (1...

    2 Answers · Science & Mathematics · 19/01/2012

  7. sec (2 - 3x)^2 * sin(2 - 3x) / (1 - sec (2 - 3x))^(1/2) => (1/cos(2 - 3x)^2) * sin(2 - 3x) / (1 - 1/cos(2...1/3) * du / ((u + 1)^2 * sqrt(u)) u = tan(t)^2 du = 2 * tan(t) * sec (t)^2 * dt (-1/3) * 2 * tan(t) * sec (t)^2 * dt / ((1 + tan(t)^2)^2...

    1 Answers · Science & Mathematics · 19/02/2013

  8. sec (x√3) dx Let u = x√3 du = √3 dx 1/√3 ∫ sec (u) du 1/√3 [ln| sec (u) + tan(u)| + C] ln| sec (x√3) + tan(x√3)| / √3 + C

    4 Answers · Science & Mathematics · 24/08/2011

  9. sec ^3(x) dx = ∫ sec (x) sec ^2(x) dx from [ 0 to π/4 ] integrate by parts u = sec x du = sec (x) tan(x) dv = sec ^2(x) dx v...π/4 ) tan(π/4) - 0 ] + (1/2) [ ln I sec (π/4) + tan(π/4) - ln I sec (0) + tan...

    2 Answers · Science & Mathematics · 03/01/2012

  10. ∫ ( 1/(1 - sec (x)) dx ) We can't solve this directly; let's use identities. Multiply the top and bottom by (1 + sec (x)) gives us (1 + sec (x)) / (1 - sec²(x)) The bottom...

    3 Answers · Science & Mathematics · 18/03/2007

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