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I = ∫

**sec**^5(x) dx = ∫ (sin^2(x) + cos^2(x))***sec**^5...**sec**^3(x) dx Note: d(sin(x)***sec**^4(x)) = cos(x)***sec**^4(x) dx + sin(x)*4sec...1/2)**sec**(x) dx I = (1/4)sin(x)***sec**^4(x) + (3/4)*(1/2) sin(x)***sec**^2(x) - (3...1 Answers · Science & Mathematics · 30/03/2013

**sec**^-1(x)=an angle, for our case, theta, Lets use the unit circle and basic definitions to determine...z Cos = x/z Tan = y/x and using the trigonometric identities Csc = 1/sin**Sec**= 1/cos Cot = 1/tan we get Csc = z/y**Sec**= z/x Cot = x/y So, to answer...5 Answers · Education & Reference · 08/06/2011

As an

**SEC**fan and supporter, I agree. I believe that the Big Ten... know that college football is cyclical. The time will come for the**SEC**to have an unimpressive conference, too, once the rest of the country begins to stop...12 Answers · Sports · 20/11/2007

The

**SEC**touts as its mission statement, “…to protect investors, maintain...good because many of us need all the help we can get. As a part of the**SEC**’s mission the belief is that in order to sustain and advance economic growth, capital...2 Answers · Business & Finance · 23/04/2008

**SEC**Divisional Tie-Breaker THREE (OR MORE) TEAM TIE... following the last weekend of regular-season games shall be the divisional representative in the**SEC**Championship Game, unless the second of the tied teams is ranked...1 Answers · Sports · 09/11/2013

**sec**(2x) = 1/cos(2x) The period of cos (2x) can be found using... In this case B = 2. So the period of cos(2x) = period of**sec**(2x) = 2pi/2 = pi or 180 degrees The amplitude is defined...1 Answers · Science & Mathematics · 15/07/2013

tan(x) +

**sec**(x) = 2cos(x) Change everything to sines and cosines... work, by plugging them into the original. tan(x) +**sec**(x) = 2cos(x) Test x = pi/6: tan(pi/6) +**sec**(pi/6) = 2cos(pi/6...6 Answers · Science & Mathematics · 24/07/2008

∫

**sec**^4 (x/2) dx = ∫**sec**^2 (x/2) ***sec**^2 (x/2) dx = ∫[1 + tan^2 (x/2)] ***sec**^2 (x/2) dx = ∫**sec**^2 (x... tan(x/2) = u for the second integral => (1/2)**sec**^2 (x/2) dx = du =>**sec**^2 (x/2) dx = 2du => Integral...2 Answers · Science & Mathematics · 28/01/2011

∫

**sec**(x/2)dx Multiply numerator and denominator by (**sec**(x/2)+tan(x/2) and get ∫**sec**(x/2)dx= ∫{**sec**(x/2)(**sec**(x...x/2)tan(x/2)} dx= dt i.e dx =2dt/{ sec²(x/2) +**sec**(x/2)tan(x/2)} Subsituting ∫{sec²(x...5 Answers · Science & Mathematics · 09/03/2011

∫

**sec**^4 x dx = ∫**sec**^2 x**sec**^2 x dx Integrate by parts dv=**sec**^2 x dx; v = tan x; u =**sec**^2 x ; du = 2**sec**^2 x tan x ∫ u dv = u v - ∫ v du...3 Answers · Science & Mathematics · 11/03/2014

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