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A very large capacitor fed by a suitable high current resistor - eg. a headlamp bulb. Add a relay across the cap so it pulls in once the voltage is high enough, and shorts out the lamp. Or, far simpler and more reliable: Use a changeover relay on the output of the amp with a much...

3 Answers · Science & Mathematics · 30/03/2020

... = y/r cosΘ = x/r tanΘ = sinΘ/cosΘ = y/x

**sec**Θ = 1/cosΘ = r/x cscΘ = 1/sinΘ = r/y cotΘ...3 Answers · Science & Mathematics · 30/03/2020

... I kg-m^2, given that the angular velocity is 12.6 rad/

**sec**. In the second condition: I = I - 12/100 x I = 0...2 Answers · Science & Mathematics · 26/03/2020

P = 2pi√(L/g) P = 2pi√(15.6/9.81) P = 7.92

**sec**From max displacement to equilibrium is 1/4 cycle, so 0.25 * 7.92 = 1.98 seconds2 Answers · Science & Mathematics · 24/03/2020

mass of ball m = 98N / 9.8m/s² = 10 kg spring constant k = F/x = 98N / 1.09m = 89.9 kg/s² First you must find if the the system is overdamped, underdamped, or critically damped: c² - 4mk is (100kg/s)² - 4*10kg*89.9kg/s² is 6403...

2 Answers · Science & Mathematics · 22/03/2020

Use the equation... i = -Vo/R*ln(1 - iR/Vo) i = 7.1, Vo = 32, R = 3.2, L = 3, t = ? now transpose equation to make t the subject... plug in the values & t = 1.16

**secs**1 Answers · Science & Mathematics · 14/03/2020

...x)) dy/dx = sqrt(x) * sqrt(1 - x) / (2 * x * (1 - x)) y = arctan(x^2) tan(y) = x^2

**sec**(y)^2 * dy = 2x * dx dy/dx = 2x /**sec**(y)^2 dy/dx = 2x / (1 + tan(y)^2) dy/dx = 2x...2 Answers · Science & Mathematics · 12/03/2020

T = R*C = 5.0 *110 = 0.55 msec 8/51 = 1-e^-k 43/51 = e^-k k = -ln 43/51 = 0.1706 = t/T t = T*0.1706 = 94 μ

**sec**1 Answers · Science & Mathematics · 10/03/2020

A. Time per cycle = 60 / 2000

**sec**. Work per cycle = 600 kW * 60 / 2000**sec**. Remember that 1 kW = 1000 J/**sec**. B. 600 kW / 0.4 * 0.61 Answers · Science & Mathematics · 04/03/2020

1) centripetal acceleration a = r w’2 = 1.2 x( 1.82x6.28)’2 = 156.76 m/

**sec**’2 2) centripetal force fc= m a = 1337.2 N.4 Answers · Science & Mathematics · 01/03/2020

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