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  1. sec^8(x) * √(tan^3(x)) dx = ∫sec^6(x) * sec^2(x) * √(tan^3(x)) dx Note that 1 + tan^2(x...sec^2(x) * √(tan^3(x)) dx Now let z = tan(x) => dz = sec^2(x) dx = ∫(1 + z^2)^3 * z^(3/2) dz Now basically expand...

    2 Answers · Science & Mathematics · 31/03/2014

  2. sec(2x) = [sec^2(x)] / [2 - sec^2(x)] Your first step would be to choose the more complex side. I'm... = 1 / cos(2x) Which, by definition is equal to RHS = 1 / cos(2x) = sec(2x) = LHS

    7 Answers · Science & Mathematics · 01/01/2007

  3. y = sec (xy^3) y' = sec(xy^3) tan(xy^3) d/dx (xy^3) y' = sec(xy^3) tan(xy^3) [ y^3 + x (3y^2) y' ] y' = sec(xy^3) tan(xy^3) [ y^3...

    1 Answers · Science & Mathematics · 01/10/2012

  4. f(x) = sec x = 1/cos x....................f(0) = 1 f'(x) = sin x/(cos² x...cos^5 x + 720 sin^6 x/cos^7 x f<6>(0) = 61 f(x) = sec x = 1 + x^2/2 + 5 x^4/4! + 61 x^6/6! +.... sec x = 1 + x^2/2 + 5x^4/24...

    1 Answers · Science & Mathematics · 08/11/2008

  5. ...may not affect your reading of my answer. I dislike the SEC because it seems that year in and year out, the SEC, more than any other...

    10 Answers · Sports · 20/08/2008

  6. (sec x + tan x)cos x - sin x = 1 => In trigonometry, sec x = 1/cos x & tan x = sin x/cos x, then (1/cos x + sin x/cos x)cos x - sin x...

    3 Answers · Science & Mathematics · 20/10/2013

  7. sec^2x sin^2x = sec^4x - (tan^4x + sec^2x) (1/cos^2x)sin^2x ==== (1/cos^4x) - (sin^4x/cos^4x) - (1/cos^2x...

    2 Answers · Science & Mathematics · 07/05/2019

  8. ∫ tan^2(x) sec x dx ∫ [ sec^2(x) - 1 ] sec x dx = ∫ sec^3(x) dx - ∫ sec x dx first one integrate by parts let u = sec x : du = sec x tan x dx dv = sec^2(x) dx : v = tan x ∫ sec^3(x) dx = sec x...

    1 Answers · Science & Mathematics · 11/03/2009

  9. Triple Sec is used for Tequila Margarita, but you...on top of the Kahlua. Finally top with Triple Sec - also poured over the spoon. Serve :)

    2 Answers · Food & Drink · 12/03/2009

  10. (sec ² x - 1) / sec ² x 1 - 1 / sec ² x 1 - cos ² x (1 - cos x)(1 + cos x)

    3 Answers · Science & Mathematics · 09/04/2008

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