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  1. d = 2t² – 4t v = dd/dt = 4t – 4 v(3) = 4•3 – 4 = 8  something/ sec

    1 Answers · Science & Mathematics · 23/11/2020

  2. ...you can split the  | v  |   into pieces... it is = 0  at t = 5/9 sec    so  2 integrals  ...     -1  *  ∫ ( 9t- 5 )dt    from 0 to 5/9...

    2 Answers · Science & Mathematics · 22/11/2020

  3. ...m3)/2*V^2 V = √((3*9,806*(19-7.8)-32*3)/((19+7.8+14)/2) = 3.4 m/ sec ^2 Through dynamics  accelerating force AF = (m3-m1)*g-32...

    3 Answers · Science & Mathematics · 21/11/2020

  4. (a) solve y = y₀ + v₀t + ½at² 0 = 48 + 16t - 16t² has roots at t = -1.3 s ← ignore and t = 2.30 s ← solution (b) v = v₀ + at = 16ft/s - 32ft/s²*2.3s = -57.689 ft/s OR v = √(u² + 2gh) = √(16² + 2*32*48) ft/s = -57.689 ft/s...

    1 Answers · Science & Mathematics · 17/11/2020

  5. ...velocity  Voy  Vo = Voy*sen 37° = 25*0.6 = 15.0 m/ sec   How long (t) will it take the ball to reach its highest point...

    2 Answers · Science & Mathematics · 17/11/2020

  6. a = -g*μ = -0.28*9.806 = -2.75 m/ sec ^2  d = (0-(51/3,6)^2 / (-2.75*2) = 36.5 m 

    1 Answers · Science & Mathematics · 17/11/2020

  7. Answer: 140m Observe motion of car relative to truck. For observer in truck, initially they both seem at rest, then car starts to accelerate and moves from 38m behind to 11m in front, apparently covering distance s = 38 + 11 = 49m. The time required is t...

    1 Answers · Science & Mathematics · 21/11/2020

  8. ... = ( 2*Vo*sin@ ) / g  = ( 2*40 * sin (40˚)  ) / 9.8  = 5.247 sec      [ proj. motion eqn ] at that point  the arrow  has  Velocity...

    2 Answers · Science & Mathematics · 13/11/2020

  9. ...he cleared the crossbar time to travel 38 m, t = 38 m / 16.06 m/s = 2.366 sec which means it fell for 2.366 s – 1.820 s = 0.546 s how far from...

    1 Answers · Science & Mathematics · 10/11/2020

  10. ...to question 3  acceleration a = g*(m1-m2)/(m1+m2) = 9.8(1.06-1)/(2.06) = 0.2854 m/ sec ^2  answer to question 4 accel. a' = (9.8*(1.06-1)-0.056)/(2.06) = 0.2583 m/ sec ...

    2 Answers · Science & Mathematics · 01/11/2020

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