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11.854 ft greatest height = 13 ft . . . at t = 5

**sec**1 Answers · Science & Mathematics · 17/01/2021

Use the trig identity sin² A + cos² A = 1 49/65 + cos² A = 1 cos² A = 1 - 49/65 cos² A = 16/65 cos A = 4/√65

**sec**A = 1/ cos A**sec**A = √65/41 Answers · Science & Mathematics · 16/01/2021

... quadrant. cos(t) = -sqrt(2)/2, sin(t) = -sqrt(2)/2, tan(t) = 1, cot(t) = 1,

**sec**(t) = -sqrt(2), csc(t) = -sqrt(2). #10. Angle is in the 4th quadrant...1 Answers · Science & Mathematics · 07/01/2021

In imperial units g = 32.174 ft/s² d = v² sin 2θ / g d = 291² * sin(2*45°) / 32.174 = 2632 ft = 877yd 1ft In SI g = 9.807 m/s² v = 88.7 m/s d = v² sin 2θ / g d = 88.7² * sin(2*45°) / 9.807 = 802.3 m Derivation of formula In...

1 Answers · Science & Mathematics · 14/12/2020

...(t) = 0, so, 5t^2 = 180 t^2 = 36 (and we only need positive time t) t = 6 secs 6) Dropped means no initial velocity. v(t) = dS/dt = gt = -10t...

3 Answers · Science & Mathematics · 05/01/2021

If cot θ = 3/4, which of the following is NOT true? Answer: a.

**sec**θ = 4/53 Answers · Science & Mathematics · 16/12/2020

h²= x² + y² x= 4 + 3*3= 13 17²= 13² + y²; y= √120= 2√30 h*dh/dt= x*dx/dt + y*dy/dt 0= 13*3 + 2√30*dy/dt dy/dt= -39/(2/√30)≈ -3.56 ft/

**sec**1 Answers · Science & Mathematics · 07/12/2020

V' = 4 π r² r '......- 40π cm³ /

**sec**1 Answers · Science & Mathematics · 05/12/2020

... = ∫ F * distance ρgdV = Force [ kg/m^3 ] * ( m/

**sec**^2 ) * { m^3 } = kg m/**sec**^2 = Newtons... ρ = density 1000 kg/m^3...2 Answers · Science & Mathematics · 03/12/2020

int over [ - π / 3 , π / 3 ] of { π [ ( 6 - 4)² - (4 +

**sec**x - 4)² ] dx }1 Answers · Science & Mathematics · 27/11/2020