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...tan(y) / (1 + 3 tan^2(y)) = 2 tan(y) / (1 + tan^2(y) + 2 tan^2(y)) = 2 tan(y) / (

**sec**^2(y) + 2 tan^2(y)) This is the part where you want to break everything...2 Answers · Science & Mathematics · 15/01/2021

a.) cos(pi/4) = 1/rt2,

**sec**= 1/cos. Therefore**sec**(pi/4) = 1/(1/rt2) = rt2.; b.) sin(7pi/6) = sin(pi...1 Answers · Science & Mathematics · 21/07/2020

cosx = 0 ---> x=(π/2)+nπ where n ∊ℤ

5 Answers · Science & Mathematics · 15/07/2020

Presuming that is: [tan(x) + 1] / [tan(x) - 1] = [

**sec**(x) + csc(x)] / [**sec**(x) - csc(x)] tan(x) = sin(x) / cos(x)**sec**(x) = 1 / cos(x) csc(x...2 Answers · Science & Mathematics · 02/07/2020

...x = 1, cos^-1(1) -- sometimes called arccos(1) = 0. 1/(cos(1)), or

**sec**(1), is irrational. b) is the only true statement.2 Answers · Science & Mathematics · 07/05/2020

Clearly D). x-intercepts appear when y = 0. Since

**sec**(x) = 1/cos(x), you have at best a unit fraction, one whose numerator...2 Answers · Science & Mathematics · 02/06/2020

...; t < pi and 3pi/2 < t < 2pi

**sec**(t) is negative in Q2 and Q3 pi/2 < t <...4 Answers · Science & Mathematics · 17/02/2020

...have 0/0, so we can use L'hopital's rule u = arctan(x/5) tan(u) = x/5

**sec**(u)^2 * u' = 1/5 u' = (1/5) /**sec**(u)^2 u' = 1 / (5 * (1 + tan(u)^2)) u...3 Answers · Science & Mathematics · 07/11/2019

position are P(a , b) sin(t) = b/√(a^2+b^2) cos(t) = a/√(a^2+b^2) tan(t)=b/a csc(t)=1/sin(t)=...

**sec**(t)=1/cos(t)=... cot(t)=1/tan(t)=...1 Answers · Science & Mathematics · 19/06/2019

...1 rev/32s x 2π rad/rev = π/16 rad/s k is the time offset, which would be ??

**sec**at t=10, must be at a max, which makes angle 90º, π/2 π/2 = ω...1 Answers · Science & Mathematics · 18/06/2019

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