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**sec**(x) - sin(x) = [tan^2(x) + cos^2(x)] / [**sec**(x) + sin(x)] LS:**sec**(x) - sin(x) = [**sec**(x) - sin...x) = 1 dividing through by cos^2(x) tan^2(x) + 1 =**sec**^2(x) tan^2(x) =**sec**^2(x) - 1 resubstituting tan^2(x): =**sec**...2 Answers Â· Science & Mathematics Â· 30/11/2009

x * tan(x) * dx / (

**sec**(x) + tan(x)) => x * tan(x) * (**sec**(x) - tan(x)) * dx / (**sec**(x)^2 - tan(x)^2) => x * (tan(x) ***sec**(x) - tan(x)^2) * dx / 1 => x * (**sec**(x) * tan(x) -**sec**(x)^2 + 1) * dx u = x du = dx dv =**sec**(x) * tan(x) * dx -**sec**(x...3 Answers Â· Science & Mathematics Â· 29/04/2013

âˆ«

**sec**[(5/2)x] tan[(5/2)x] dx = (I assume x is in the numerator) let [(5/2)x] = u â†’ x = (2/5)u â†’ dx = (2/5) du then, substituting, you get: âˆ«**sec**(5/2x) tan(5/2x) dx = âˆ«**sec**u tan u (2/5) du = take out the constant: (2/5) âˆ«**sec**...3 Answers Â· Science & Mathematics Â· 14/08/2008

y*

**sec**(x) = x*tan(y) Differentiating both sides with respect to x, y * d/dy(**sec**(x)) +**sec**(x) * dy/dy = x * d/dy(tany) + tan(y) * dx/dy Or y * d/dy(**sec**(x...2 Answers Â· Science & Mathematics Â· 18/07/2009

The

**SEC**has only lost 1 BCS game since 2001. By contrast, Choke...also blistered the ACC champion by 41 points. The**SEC**'s bowl record is more impressive when considering they play few ...18 Answers Â· Sports Â· 03/01/2008

1+

**sec**(x)=tan(x) 1+**sec**(x)=sin(x)/cos(x) Crossing multiplication. cos(x)(1+**sec**(x))=sin(x) (cos(x)+1)^2=(sin(x))^2 cos^2(x)+2cos(x)+1=sin^2(x) ..... ... ...11 Answers Â· Science & Mathematics Â· 02/08/2013

Triple

**sec**is an orange flavored liqueur that is used in ...and it will be noted on the bottle. The two most popular high end triple secs in the states are Grand Marnier (it's ...8 Answers Â· Food & Drink Â· 28/12/2007

First, a few identities: [a]

**sec**x = 1 / cos x [b] csc x = 1 / sin x [c] cos x + n360 = cos x...90. 5) Apply [i], [j] or [k] if possible. So...**sec**-150 = 1/cos -150 [a] = 1/cos 150 [e] = -(1/cos 30) [g] = -(1...1 Answers Â· Science & Mathematics Â· 03/12/2007

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**sec**(âˆšx) / âˆšx dx let âˆšx =t (1(/2âˆšx))*dx=dt substitute âˆ«**sec**(âˆšx) / âˆšx dx=âˆ« 2**sec**t dt =2ln|**sec**t+tant|+C t=âˆšx hence âˆ«**sec**(âˆšx) / âˆšx dx...2 Answers Â· Science & Mathematics Â· 22/06/2013

**sec**^2(18) - tan^2(18) First off, remember that there is an identity that relates**sec**^2(x) with tan^2(x); it goes**sec**^2(x) = tan^2(x) + 1. Therefore...6 Answers Â· Science & Mathematics Â· 13/03/2007

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