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= sec²(y).[1 + csc(y)] → you know that:

**sec**(x) = 1/cos(x) = [1/cos²(y)].[1 + csc(y)] → you know that: csc(x) = 1/sin(x...sin(y) = a = 1/[a.(1 - a)] = 1/(a - a²) ← memorize this result as (1) = tan(y).[**sec**(y) + tan(y)] → you know that:**sec**(x) = 1/cos(x) = tan(y).[{1/cos(y)} + tan(y)] → you...3 Answers · Science & Mathematics · 27/02/2019

y=

**sec**(x/3+pi)=> y=-**sec**(x/3)=> y=-1/cos(x/3) The period T=6pi There is...5 Answers · Science & Mathematics · 18/08/2019

**sec**^2 x = 1 + tan^2 x = 1 +(-5/3)^2 = 34/9**sec**x = - sqrt(34/9) = - sqrt(34)/3 we use the -ve sign since cos x is -ve in the quad 21 Answers · Science & Mathematics · 26/04/2019

period T = Δt/Δn = (30

**sec**) / 25 rev = 6/5 = 1.2**sec**/rev angular speed ω = 2PI/T = 1.(6)*PI...1 Answers · Science & Mathematics · 12/06/2019

csc(t) = 1/sin(t)

**sec**(t) = 1/cos(t) That angle is 360 degrees - 45 degrees = 315 degrees cos(315 degrees) = 0.7071 = sqrt(2)/2 sin(315 degres) = -0.7071 = -sqrt(2)/2 so**sec**(t) = 2/sqrt(2) = sqrt(2) etc...2 Answers · Science & Mathematics · 06/09/2019

g = 5.61*2 = 11.22 m/

**sec**^2 V = -g*t = -11.22*2 = -22.44 m/**sec**Δh = -g/2*t^2 = -5.61*2^2 = -22.44 m4 Answers · Science & Mathematics · 03/09/2019

...λ) = 578nm = 578 x 10⁻⁹m Speed of light (c) = 3 x 10⁸m/

**sec**Frequency (f) = ? We know that:- Frequency (f) = speed of...3 Answers · Science & Mathematics · 20/04/2019

... 1g = -32.17405 ft/s2 so 1.25-g = 1.25 * 32.17405 ft/s2 = 40.2175625 ft/

**sec**^2 so there are 12 inches in a foot 1.25-g = -40.2175625*12 inch...2 Answers · Science & Mathematics · 03/06/2019

Refer to the sketch below. We have that tanθ = -3/5, sinθ = -3/√34 and cosθ = 5/√34 Now,

**sec**θ => 1/cosθ i.e. 1/(5/√34) = √34/5 :)>3 Answers · Science & Mathematics · 12/08/2019

sin(2Θ) = 2sinΘcosΘ cosΘ = -√(1-sin²Θ) :

**sec**Θ < 0 → cosΘ < 0 sin(2Θ) = -2sinΘ√(1-sin²Θ) = - (2/25)√24 = -4√6/25 ≈ -0.391921 Answers · Science & Mathematics · 30/05/2019