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1. ### Where the hell do I sit in this concert?

i would just ask the people that work there when you get there

2 Answers Â· Entertainment & Music Â· 04/09/2019

2. ### help with physics?

Î”V = 50âˆš2/3.6 = 19.64 m/sec t accel. = Î”V/ Î”t = 19.64/5 = 3.93 m/sec^2

2 Answers Â· Science & Mathematics Â· 16/08/2019

3. ### If a current of 0.850 A is applied to the electrochemical cell in Figure 1 for 2.00 h, then the mass of copper produced is?

0.85 A * 7200 sec = coulombs of current Coulombs / 96500 = Faradays of current...

1 Answers Â· Science & Mathematics Â· 13/08/2019

4. ### A 65kg TV is dropped from a window 2.5m above ground. What is the TV's speed just before it strikes the ground? (7 m/s)?

conservation of energy : m*g*h = m/2*V^2 mass m cross (which means that this formula is applicable to whatsoever mass) V = âˆš2*g*h = âˆš5*9,80 = âˆš49 = 7.0 m/sec

3 Answers Â· Science & Mathematics Â· 18/07/2019

5. ### Trig Ratios Math Question Help?

position are P(a , b) sin(t) = b/âˆš(a^2+b^2) cos(t) = a/âˆš(a^2+b^2) tan(t)=b/a csc(t)=1/sin(t)=... sec(t)=1/cos(t)=... cot(t)=1/tan(t)=...

1 Answers Â· Science & Mathematics Â· 19/06/2019

6. ### Function Math Problem Help??

...1 rev/32s x 2Ï€ rad/rev = Ï€/16 rad/s k is the time offset, which would be ?? sec at t=10, must be at a max, which makes angle 90Âº, Ï€/2 Ï€/2 = Ï‰...

1 Answers Â· Science & Mathematics Â· 18/06/2019

7. ### Sec(theta)=13/12 and is in the fourth quadrant.?

cosÎ¸ = 12/13 sinÎ¸ = -5/13 cscÎ¸ = -13/5 cotÎ¸ = -12/5

2 Answers Â· Science & Mathematics Â· 04/06/2019

8. ### I want to shut off my phone for a week...need help?

A phone is for calls! Not texting. Sigh. This d a m n generation. Ignore texts. Answer calls only.

4 Answers Â· Family & Relationships Â· 22/05/2019

9. ### Prove that sec^2x sin^2x = sec^4x - (tan^4x + sec^2x) is an identity?

sec^2x sin^2x = sec^4x - (tan^4x + sec^2x) (1/cos^2x)sin^2x ==== (1/cos^4x) - (sin^4x/cos^4x) - (1/cos^2x...

2 Answers Â· Science & Mathematics Â· 07/05/2019

10. ### Write rectangular equation for the parametric equation: x=tan^2(theta) y=sec^2(theta)?

x = tanÂ²(Î¸) y = secÂ²(Î¸) secÂ²(Î¸) - tanÂ²(Î¸) = 1 y - x = 1 x - y + 1 = 0, where x â‰¥ 0, y â‰¥ 1 The graph of the equation is a ray.

2 Answers Â· Science & Mathematics Â· 07/05/2019