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  1. sec ^4 x dx = ∫ sec ^2 x sec ^2 x dx Integrate by parts dv= sec ^2 x dx; v = tan x; u = sec ^2 x ; du = 2 sec ^2 x tan x ∫ u dv = u v - ∫ v du...

    3 Answers · Science & Mathematics · 11/03/2014

  2. Separate the integral to sec (4x) tan (4x) since the derivative of sec x is sec x tan x, we'll need this...change tan^2 into sec ^2 - 1 (trigonometry identity) Integral (( sec (4x) tan (4x) sec ^2 (4x) ( sec ^2 (4x) - 1) dx) Use u substitute for sec (4x). Derivative...

    3 Answers · Science & Mathematics · 04/12/2011

  3. To remember sec -butyl, I always find it helpful to remember what the " sec " actually ...secondary carbon atoms (attached to two other carbons). The sec -butyl group is attached to the parent molecule via one of these " sec ...

    6 Answers · Science & Mathematics · 07/07/2010

  4. y = sec (8^x) tan [ (1+e^x) /(1-e^x)] Apply the product rule: dy/dx = d/dx sec (8^x) tan [ (1+e^x) /(1-e^x)] + sec (8^x) d/dx... (3) into (2) d/dx tan [ (1+e^x)/(1-e^x)] = sec ^2 [ (1+e^x)/(1-e^x)] times -2e^(2x) / (1...

    2 Answers · Science & Mathematics · 19/01/2012

  5. sec (2 - 3x)^2 * sin(2 - 3x) / (1 - sec (2 - 3x))^(1/2) => (1/cos(2 - 3x)^2) * sin(2 - 3x) / (1 - 1/cos(2...1/3) * du / ((u + 1)^2 * sqrt(u)) u = tan(t)^2 du = 2 * tan(t) * sec (t)^2 * dt (-1/3) * 2 * tan(t) * sec (t)^2 * dt / ((1 + tan(t)^2)^2...

    1 Answers · Science & Mathematics · 19/02/2013

  6. sec (x√3) dx Let u = x√3 du = √3 dx 1/√3 ∫ sec (u) du 1/√3 [ln| sec (u) + tan(u)| + C] ln| sec (x√3) + tan(x√3)| / √3 + C

    4 Answers · Science & Mathematics · 24/08/2011

  7. sec ^3(x) dx = ∫ sec (x) sec ^2(x) dx from [ 0 to π/4 ] integrate by parts u = sec x du = sec (x) tan(x) dv = sec ^2(x) dx v...π/4 ) tan(π/4) - 0 ] + (1/2) [ ln I sec (π/4) + tan(π/4) - ln I sec (0) + tan...

    2 Answers · Science & Mathematics · 03/01/2012

  8. ∫ ( 1/(1 - sec (x)) dx ) We can't solve this directly; let's use identities. Multiply the top and bottom by (1 + sec (x)) gives us (1 + sec (x)) / (1 - sec²(x)) The bottom...

    3 Answers · Science & Mathematics · 18/03/2007

  9. 1) sec ^2x(1-sin^2x) sec ^2x ( cos^2x) ----------------- sin^2x + cos^2x = 1 cos^2x/cos^2x --------------- sec ^2x = 1/cos^2x 1 2) cos^B/ 1-sinB 1-sin^2B / 1-...

    2 Answers · Science & Mathematics · 08/07/2011

  10. Hello, ∫ [ sec (3x) /tan(3x)] dx = let's rewrite it as: ∫ sec (3x) [1/tan(3x)] dx...up with: (1/3) ln |csc(3x) - cot(3x)| + C in conclusion: ∫ [ sec (3x) /tan(3x)] dx = (1/3) ln |csc(3x) - cot(3x)| + C I...

    1 Answers · Science & Mathematics · 05/10/2010

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