Yahoo Web Search

  1. About the center, the moment of inertia of the rod is Ic = M(3L)²/12 = 3ML²/4 and so by the parallel axis theorem, about the pivot point it's I = 3ML²/4 + M(L/2)² = ML² torque τ = M*g*(L/2) = I*α...

    1 Answers · Science & Mathematics · 14/11/2020

  2. yup  good so far...  don't forget to choose a Best answer.... Though I like  tan (2@) = B / ( A - C )  = -4/3  we can work with cotangent also..  Draw rt triangle  in QII   [ in Q II since  cot = -  in Q II ] ......  i'll use...

    1 Answers · Science & Mathematics · 12/11/2020

  3. As the load swings down to the equilibrium position, it converts PE to KE. The moment of inertia of the system is I = mL²/12 + 2m*(L/2)² = 7mL²/12 The maximum speed is at the bottom of the arc: 2m*g*(L/2...

    1 Answers · Science & Mathematics · 14/11/2020

  4. Yes, that is true. During the Devonian period of of the Paleozoic era Earth's day was only 16 hours and approximately 20 minutes long according to oxygen isotope ratios in the shells of coral fauna and flora...

    6 Answers · Science & Mathematics · 20/11/2020

  5. ...1176 N·m positive by convention. girl: must be -1176 N·m (d) No rotation means the net torque is zero. (e) x = d * m/M = 4m * 30/45 = 2...

    1 Answers · Science & Mathematics · 08/11/2020

  6. Yes, which sucks because my grandmother usually visits us from Florida and spends the holiday weekend with us. Or we go to visit her. I probably won't get to see her at all until sometime next year...

    8 Answers · Entertainment & Music · 25/11/2020

  7. Total KE = KE(linear) + KE( rotational )  K = ½mv² + ½Iω² For solid...

    1 Answers · Science & Mathematics · 18/11/2020

  8.      τ = FR 250 = F(0.52)     F = 480.7692      F ≈ 481 N Please remember to select a Favorite Answer from among your results.

    1 Answers · Science & Mathematics · 22/11/2020

  9. ... means the rotating arm OP will rotate for 3 complete rotation and will stop at the indicated position P 14° short of 360 ( ie 14...

    2 Answers · Education & Reference · 17/11/2020

  1. Try asking your question on Yahoo Answers