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  1. How to do a volume of revolution: The formula is: PI*S{f(x)^2... a new region to revolve. How we find the volume of revolution of the new region is we find the volume under f(x) and that...

    3 Answers · Science & Mathematics · 07/06/2009

  2. ...of the ellipse and tangent to the ellipse. We can find the volume of revolution by considering the volume of washers. Since...4 [ pi/2 - 0] 2*pi^2*a*b^2 That would be the volume of revolution. --charlie

    1 Answers · Science & Mathematics · 21/02/2013

  3. ... will use the washer method: Take a strip perpendicular to the axis of revolution (x-axis is horizontal)...and strips are vertical. Then rotate...

    1 Answers · Science & Mathematics · 06/06/2010

  4. First off, here we are talking about do a solid of revolution about the x-axis, given a function r(x): Ok, graph y = r(x) <...

    2 Answers · Science & Mathematics · 13/07/2009

  5. ... for here. Another way, is parametrizing the surface of revolution then integrating twice over the parameters. But then we need...

    1 Answers · Science & Mathematics · 05/06/2008

  6. ...the area and (b) the distance that the centroid of the area travels during the revolution. In your problem, the area is int. x = 0 to 2 of x^3 dx = (1...

    1 Answers · Science & Mathematics · 01/03/2015

  7. ...2 = b^2(1 - (x/a)^2) ...Nice- no more square root. So, the volume of revolution is: PI *b^2 * Integral{ (1 - (x/a)^2) } dx from x = -a to...

    3 Answers · Science & Mathematics · 08/06/2009

  8. ...title is "Volumes of Solids of revolutions" I assume it just means volume. y...r' of the shell would be the distance from the axis of revolution (x = -1) to the current x-position. since from the origin to...

    1 Answers · Science & Mathematics · 01/04/2008

  9. ... integral represents the volume of the solid of revolution: where R(x) is the distance between the function...if the rotation is around the x-axis (horizontal axis of revolution), or if the rotation is around the y-axis (vertical axis...

    3 Answers · Science & Mathematics · 13/05/2008

  10. hi area revolution = 2 pi int (y * (1+(y')^2)^1/2) dx = 2 pi int (cos x * (1+sin^2 x)^1/2 dx...

    3 Answers · Science & Mathematics · 29/04/2007

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