(10.0 g NI3) / (394.72011 g NI3/mol) x (-290.0 kJ / 2 mol NI3) = -3.67 kJ
1 Answers · Science & Mathematics · 22/02/2021
55.8 g is i mole of Fe. According to the reaction given, it takes 4 moles of Fe to produce 1648 kJ. So: 1648 kJ / 4 = 412 kJ released .
1 Answers · Science & Mathematics · 04/02/2021
The equation is: 51.9 kJ / 0.179 mole = 290 kJ/mol
1 Answers · Science & Mathematics · 04/02/2021