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  1. (10.0 g NI3) / (394.72011 g NI3/mol) x (-290.0 kJ / 2 mol NI3) = -3.67 kJ

    1 Answers · Science & Mathematics · 22/02/2021

  2. 55.8 g is i mole of Fe.  According to the reaction given, it takes 4 moles of Fe to produce 1648 kJ.  So: 1648 kJ / 4 = 412 kJ released .

    1 Answers · Science & Mathematics · 04/02/2021

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