Yahoo Web Search

  1. ...be maximized by making R as large as possible, subject to the constraint that L cannot be negative. So, L ... the maximum, which means the track is circular, with circumference 1 mile...

    2 Answers · Science & Mathematics · 30/09/2009

  2. ...perimeter = 2L + 2π r = 600 ---> L + π r = 300 L = length of straight track > = 200 r = radius of semicircular tracks ... = area = πr² + 2rL L + π r = 300 ==> 200 + π r = 300 r = 100/π...

    3 Answers · Science & Mathematics · 18/03/2008

  3. ...portion (147.16 ≥ L ≥ 73.08) and then calculate radius of inside of running track ( r =(200- L )/π) Once you've decided on L and r , it is fairly...

    1 Answers · Science & Mathematics · 30/10/2009

  4. if your track is circular then it would be 6pi if you go from the inside of 3 to the inside of 5 because 1.5 from 3 to 4 and 1.5 from 4 to 5 so 3 2pi( r ) is circumference so 2(3)pi 6pi

    1 Answers · Science & Mathematics · 15/02/2008

  5. the perimeter is 500 = 2 L + 2 pi r and the width of the track is 2r ( L is the length of the rectangle) with this constraint L ...

    2 Answers · Science & Mathematics · 01/02/2010

  6. 400 = 2.54 + 2 pi R + 0.6pi 397.46 = 2 pi R + 0.6 pi 397.46 = 2 pi R + 1.885 395.58 = 2 pi R 395.58 = 6.28318 R R = 395.58 / 6.28318 R = 62.95856 M

    2 Answers · Science & Mathematics · 10/04/2008

  7. lim{n-->inf}(1+( r /n))^n = lim{n-->inf}e^[nln(1+( r /n))] = lim{n-->inf}e^[ln(1+( r /n))/(1/n)] = lim{x-->0}e^[ln(1+(rx))/(x)], where x = 1/n = lim{x-->0}e^[ r /(1+rx)], using L 'Hopital's rule = e^ r

    3 Answers · Science & Mathematics · 26/11/2010

  8. Let the center of the left curve be L , the center of the right curve be R . And let the point of intersection of both rails be X . LX...

    2 Answers · Science & Mathematics · 12/09/2016

  9. A = 2 r L + pi r ^2 is to be maximized P = 2L + 2 pi r = 1500...2 A'( r ) = 1500 - 4 pi r + 2 pi r = 1500 - 2 pi r = 0 r = 1500/(2 pi) r = 750/pi so L = 0 and there is only the joined semi-circles at the end, no...

    1 Answers · Science & Mathematics · 01/02/2013

  10. ... ( L ), so L = 200 - π r Area of rectangular area inside track = d * L A = 2 r * (200 - π r ) A = 2 (200r - π r²) Find A', set...

    1 Answers · Science & Mathematics · 09/11/2009

  1. Try asking your question on Yahoo Answers