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1. ### A ball rolls around an L -Shaped track at 85rpm?

53cm. = 0.52m. Radius = 0.26m. Perimeter = 1.634 metres. This is covered 85 x per min. (60/85) x 1.634 = 1.1534m/sec. tangential V. 30g = 0.030kg. Force = mv^2/ r = 0.1535N.

2 Answers · Science & Mathematics · 17/10/2013

2. ### A 28g g ball rolls around a 46cm cm diameter L -shaped track , shown in the figure, at 64rpm rpm .?

speed = ω r = (64rev/min * 1min/60s * 2π rads/rev) * 0.23m = 1.3 m/s

1 Answers · Science & Mathematics · 03/11/2013

3. ### A 1500kg car is racing around a 3km track . It takes the car two minutes for one revolution. CENTRIPETAL FORCE?

...period by w = 2π/T with T = 2 min = 120 s and radius r is r = L /2π being L = 3000 m the track length. Then Fc = m (2π/T)² L /2π = 2π m...

1 Answers · Science & Mathematics · 23/10/2010

4. ### A 30 g ball rolls around a 42 cm diameter L -shaped track , shown in the figure below, at 60 rpm. Rolling friction can be neglected.?

42cm.diameter = 0.21m. radius, and 30g = 0.030kg. (60/60s) = 1rps. (1 x 2pi) = 6.2832 rad/sec. V = (6.2832 x 0.21m. radius) = 1.3195 m/sec. Force = (m*v^2)/ r = (0.03 x 1.3195^2)/0.21 = 0.2487N.

2 Answers · Science & Mathematics · 12/11/2017

5. ### A race car goes around a level, circular track with a diameter of 1.00 km at a constant speed of 76 km/h.?

r = L / 2 π r = 1000 / 2 * 3.14159 = 159.155 m v = 76000 / 3600 = 21.111m a = v^2 / r = 445.679 / 159.155 = 2.8 m/s2 Goodbye

1 Answers · Science & Mathematics · 03/02/2013

6. ### Physics: Circular track question, any ideas?

... the track (i.e. the angle between the line from the object to the center of the track and the vertical), and let R be the radius of the track . The object leaves the track because the the...

1 Answers · Science & Mathematics · 13/09/2009

7. ### Physics help [ Waves ]?

...origin 'O')) with the circular track marked. Mark the front of the train at ( r ,0), 'F'. Mark the rear...shift. If the train is length L , it subtends an angle α = L ...

2 Answers · Science & Mathematics · 31/03/2013

8. ### Physics Equation:Find an expression for the block's speed at a later time t. Express your answer in terms of the variables r , v0, μk and t.?

... provided by the wall and has magnitude Fc = m v^2 / r Therefore the friction force is F_fric = μk m v^2 / r ...

1 Answers · Science & Mathematics · 26/04/2016

9. ### What is the magnitude of the net force that the track exerts on the ball?

ω = 60/60 * 2pi rad/s; r = 0.22 m; m = 0.028 kg Fx = mω^2r Fy = mg F = sqrt(Fx^2 + Fy^2)

2 Answers · Science & Mathematics · 21/10/2007