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... the track (i.e. the angle between the line from the object to the center of the track and the vertical), and let

**R**be the radius of the track . The object leaves the track because the the...1 Answers · Science & Mathematics · 13/09/2009

Let the center of the left curve be

**L**, the center of the right curve be**R**. And let the point of intersection of both rails be X . LX...2 Answers · Science & Mathematics · 12/09/2016

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**L**.A.__The_Soundtrack_.rar1 Answers · Entertainment & Music · 26/10/2012

There isn't but what you can do is were the psp on switch is slide it down and put it on hold and once your finished just switch it back.

1 Answers · Consumer Electronics · 21/08/2009

In general: Z =

**R**-j/wC + jwL. You could just find the minumum of this equation if...1 Answers · Science & Mathematics · 19/08/2012

what the hell

**r**train tracks ? braces? he probably ment all of then1 Answers · Health · 30/06/2010

... ( L ), so L = 200 - π r Area of rectangular area inside track = d * L A = 2 r * (200 - π r ) A = 2 (200r - π r²) Find A', set...

1 Answers · Science & Mathematics · 09/11/2009

lim{n-->inf}(1+(

**r**/n))^n = lim{n-->inf}e^[nln(1+(**r**/n))] = lim{n-->inf}e^[ln(1+(**r**/n))/(1/n)] = lim{x-->0}e^[ln(1+(rx))/(x)], where x = 1/n = lim{x-->0}e^[**r**/(1+rx)], using**L**'Hopital's rule = e^**r**3 Answers · Science & Mathematics · 26/11/2010

if your track is circular then it would be 6pi if you go from the inside of 3 to the inside of 5 because 1.5 from 3 to 4 and 1.5 from 4 to 5 so 3 2pi(

**r**) is circumference so 2(3)pi 6pi1 Answers · Science & Mathematics · 15/02/2008

... a year ago and finally someone mentions them Big

**L**has so many good unreleased songs yet all people talk about is...12 Answers · Entertainment & Music · 22/09/2010

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