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**quarterback**takes the ball from the line of scrimmage, runs backward for 3 yards...1 Answers · Science & Mathematics · 06/10/2019

Gravitational (i.e. weight - I don't think that weight is itself considered a force) Air drag. That is all.

4 Answers · Science & Mathematics · 07/09/2018

...you need a realistic estimate of the velocity that is appropriate for your

**quarterback**. Personally I am going to ram it into a spreadsheet and...2 Answers · Science & Mathematics · 19/11/2017

To get the angle of launch, use the trajectory equation: y = h + x·tanΘ - g·x² / (2v²·cos²Θ) and since 1/cos²Θ = sec²Θ = 1 + tan²Θ, we have y = h + x·tanΘ - (1 + tan²...

1 Answers · Science & Mathematics · 20/11/2017

pls have a look at this table made up using the following equations : time t = 10*sin Θ+√(10*sin Θ)^2+4.90*8 )/9.80 range = 10*cos Θ*t ..Θ ......sin .....cos .....time....range 38.0....0.616...0.788...1.524...12.011 38.5....0.623...0.783...1.536...12.022 39.0...

3 Answers · Science & Mathematics · 19/11/2017

If the y-axis points "downfield," then net x = 17 yds net y = 46yds - 13yds = 33 yds d = √(x² + y²) = 37 yds Hope this helps!

1 Answers · Science & Mathematics · 10/11/2017

If the initial speed of the ball is V, the vertical component of velocity is V*sin(47), and the horizontal component is V*cos(47). The time until the ball is caught is found from Vt*sin(47) = (1/2)gt^2 => V*sin(47) = (4.9 m...

1 Answers · Science & Mathematics · 23/09/2017

### A

**quarterback**throws a pass that is a perfect spiral. In other words, the football does not wobble,?The time of flight will be twice the time needed for gravity to reduce the initial vertical velocity to zero t = 2(vi/g) t = 2(19sin53 / 9.8) t = 3.1 s so the ball spins 7.3 rev/s (3.1 s) = 22.6 23 rev to the two significant figures of the question numerals. I hope this helps...

1 Answers · Science & Mathematics · 21/03/2017

Plot all displacements relative to the original location of the ball: rcvr: .. 2i - 5j mtn: . 9i dnf: ..... 10j zig: . -6i 4j zag: .12i 18j qbk: ...... - 7j ----------------------- ttl: ... 17i 20j that's the distance between the qbk and the rcvr s = sqrt(17² 20²) yds = 26.2...

1 Answers · Science & Mathematics · 27/02/2017

(a) impulse = mΔv impulse = (206lb / 32ft/s²) * -8 ft/s = -51.5 slug·ft/s = -51.5 lb·s (b) F = impulse / time = -51.5lb·s / 0.14s = 368 lb Hope this helps!

1 Answers · Science & Mathematics · 06/02/2017

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