First find the square of the velocity (there's a formula for that), then find the work done which will lead you to the force. range x = V²sin(2Θ) / g 60.0 m = V² * sin90º / 9.8m/s² V² = 588 m²/s² Then the QB gave...

1 Answers · Science & Mathematics · 04/12/2016

Use the principle of conservation of momentum to solve this problem Total momentum before collision = Total momentum after collision Before, We have momentum of line backer = M1 V1 = 116 V1 Momentum of quarter back is zero (He...

1 Answers · Science & Mathematics · 17/05/2011

Doug can catch the ball while it is rising, or at its maximum height or while it is falling depending on the initial velocity.But since douglas is at the tight end he should catch the ball while it is rising. Here we need to know the...

2 Answers · Science & Mathematics · 26/09/2006

...horizontal velocity is constant. The horizontal velocity of travel of the ball from

**quarterback**to halfback, and the horizontal velocity with which the**quarterback**throws the ball...2 Answers · Science & Mathematics · 18/06/2011

Use the trajectory eqn: y = h + x·tanΘ - g·x² / (2v²·cos²Θ) 2m = 1.8m + xtan35º - 9.8m/s² * x² / (2(12m/s)² * cos²35º) 0 = -0.2 + 0.7x - 0.0507x² quadratic in x, solutions at x = 0.29...

1 Answers · Science & Mathematics · 11/03/2012

There is a simple formula for this: range x = V²sin(2Θ) / g Here, 177 m = V² * sin67.2º / 9.8m/s² which solves to V = 43.4 m/s Seems super-exceptional to me. (That's almost two football fields, btw...

1 Answers · Science & Mathematics · 13/10/2016

The same, since momentum is always a conserved quantity, in any collision.

1 Answers · Science & Mathematics · 26/11/2013