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  1. The easy answer is twice 2.9 seconds,or 5.8 seconds, since time up usually = time down. But if you consider that it might land on the ground, it would be in the air a little longer, since the falling distance would be larger than the rising distance.

    2 Answers · Science & Mathematics · 24/08/2009

  2. It would be 2 times the time it took the ball to reach its peak. In this case, it would be 5.2

    3 Answers · Science & Mathematics · 04/11/2009

  3. 5 seconds. When at the top of its path it's halfway through its total trajectory. Think about the parabolic graph and that'll make sense. That means to find out how long it was in the air, you just have to multiply the halfway point by 2.

    2 Answers · Science & Mathematics · 25/01/2010

  4. By R = u^2sin2θ/g =>164 = u^2sin(2 x 30.8)*/9.8 =>u = √1827.09 =>u = 42.74 m/s

    2 Answers · Science & Mathematics · 24/09/2010

  5. the highest point of the arc of his throw is at a distance of 84.55 meters at a height x/84.55= tangent 30 degrees X= 84.55(.5774 ) = 48.82 meters V^2 = 2AS V^2 = 2(9.81)(48.82) = 957.85 V = 30.95 m/s

    3 Answers · Science & Mathematics · 14/11/2008

  6. Given Ux = ucosθ = 20.6 m/ & Uy = usinθ = 16.3 m/s (1) By t = usinθ/g = 16.3/9.8 = 1.66 sec (2) By H = (usinθ)^2/2g = (16.3)^2/(2 x 9.8) = 13.56 m (3) By T = 2t = 3.32 sec (4) By R = [Ux] x T =>R = 20.6 x 3.32 = 68.39 m

    2 Answers · Science & Mathematics · 19/07/2013

  7. Symbols used: v→ = horizontal velocity R = range (horizontal distance the ball moves) v = actual velocity u↑ = initial vertical velocity component v↑ = final vertical velocity component t = time for ball to reach maximum height T = time in air h = height ball reaches above point of release...

    2 Answers · Science & Mathematics · 03/10/2012

  8. as g=9.8m/s^2 d=d0+vt = 17+2t d=vt = v0cos(25)t v0cos(25)t= 17+2t ...(1) h=vyt+1/2gt^2 0= v0sin(25)t-4.9t^2 v0sin(25)t= 4.9t^2 ...(2) (2)/(1) tan(25)= 4.9t^2/(17+2t) 0.4663= 4.9t^2/(17+2t) 4.9t^2+0.9326t+7.9272=0 t= 1.3706s = 1.37[s] (Flight duration) v0cos(25)t=17+2t v0cos(25)*1.3706=17+2*1.3706 v0cos(25)= 14.4033= 14.4[m/s] (horizontal velocity) v0= 15.8923= 15...

    2 Answers · Science & Mathematics · 05/03/2014

  9. 1st Average velocity = 15/2.5 = 6 m/s 2nd Average velocity = -3/1.75 ≈ -1.714 m/s 3rd Average velocity = 21/5.2 ≈ 4.038 m/s Total average velocity = total displacement/ total time Total displacement = 15 – 3 + 21 = 33 m Total time = 2.5 + 1.75 + 5.2...

    2 Answers · Science & Mathematics · 09/09/2013

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