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related to: quarterback

...find the range of the football to determine whether the receiver runs toward the

**quarterback**or away R=v0^2 sin(2 theta)/g = 16^2 sin(60)/9.81 = 22.6m so he ...1 Answers · Science & Mathematics · 08/10/2011

... = sqrt.(15.21832^2 + 6.887^2) = 16.7m/sec. Angle relative to

**quarterback**= arctan (6.887/15.21832) = 24.35 degrees above horizontal.1 Answers · Science & Mathematics · 27/01/2016

...09 m So the receiver needs get moving forward (away from the

**quarterback**). He is 12.69 m from where the ball is going to land and...3 Answers · Science & Mathematics · 27/01/2012

Part of the system: football,

**quarterback**momentum of system: 0 solution method: conserve momentum 0 = 80kg * v + 0.43kg * 15m/s v = -0.081 m/s = -8.1 cm/s He will be moving 8.1 cm/s backward.1 Answers · Science & Mathematics · 09/03/2014

...s = t x v = 2.93 x 20.48 = 60.01 m The receiver is 20m from the

**quarterback**, so he will have to run 60.01 - 20 = 40.01 m, for 2.93 sec. His speed must...1 Answers · Science & Mathematics · 10/06/2012

This is conservation of momentum problem. Let m be the mass of

**quarterback**. Initial momentum = 151 * 4.75 = 717.25 Final momentum = (m + 151) * 2...1 Answers · Science & Mathematics · 01/07/2016

... initial kinetic energy of ball KE=MV^/2 Assume

**quarterback**can give the lighter ball (mass m, speed v) the same kinetic energy KE...3 Answers · Science & Mathematics · 09/06/2011

A football

**quarterback**throws a pass on the run and then keeps running without ...the ball to go up and back down as he run a specific horizontal distance. If the**quarterback**can satisfy the 3 conditions above, he can throw the pass and then catch it...2 Answers · Science & Mathematics · 07/10/2010

...047504898810577174357634155087 since R is more than 17.5 m the receiver runs away from the

**quarterback**. Now, I need some water.1 Answers · Science & Mathematics · 18/07/2010

Conservation of momentum m1u1 + m2u2 = (m1 + m2)v if the

**quarterback**is m2 and u2 = 0 m1u1 = (m1 + m2)v u1 = (m1 + m2)v / m1 u1 = (111.0 + 90.0)2.4 / 111.0 u1 = 4.35 m/s1 Answers · Science & Mathematics · 02/06/2013