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  1. ...2 ) xl = 300 ohms L = 300 / 2 pi 800 L = 0.0596 H for pf = 1 ----> xc = xl f = 1 / 2 pi sqrt (LC) 1000 = 1 / 2 pi sqrt(0.0596C...

    2 Answers · Science & Mathematics · 29/12/2014

  2. ...pi = 6.12 x 10^-6 F or 6.12 uF p = xi^2 = 250 x 1.2^2 = 360 w pf = p / v i = 360 / 600 x 1.2 = 0.5

    1 Answers · Science & Mathematics · 27/12/2014

  3. pf = cos φ = 0.3 sin φ = √1-0.3^2 = 0.954 = X/Z Z = X/sin φ = 40/0.954 = 41.93 ohm 0.3 = R/Z R = Z*0.3 = 41.93*0.3 = 12.58 ohm....10 ohm is wrong !!!

    2 Answers · Science & Mathematics · 26/12/2014

  4. yes...that is correct ...

    1 Answers · Science & Mathematics · 08/12/2014

  5. ...the transformer primary side. http://www.zen22142.zen.co.uk/Circuits/Alarm/pf_alm.htm If you want to detect a brown out condition (low volts like ...

    2 Answers · Science & Mathematics · 03/12/2014

  6. You can determine the PF because you know the load impedance and angle. Each phase consumes the same power and the total power is the sum of them.

    2 Answers · Science & Mathematics · 24/10/2014

  7. amount of capacity increases on LC ( series ) ....Z = sq [ R^2 + ( 2 pi f L - 1 / 2 pf f C )^2 ].......Z decreases....so voltage across R increases .

    3 Answers · Science & Mathematics · 20/10/2014

  8. The magnetising component is 0.5 x 0.954 = 0.477 amps {note that : 0.954 = sin[arc-cos(0.3)]} The working component is 0.5 x 0.3 = 0.15 amps You don't seem very good at awarding Best Answer. I like to see some...

    2 Answers · Science & Mathematics · 07/10/2014

  9. ...read in the same way as that for resistors except the base unit is pF (picoFarad, 1 pF = 10-12 F = 10-6 μF). So a...

    7 Answers · Science & Mathematics · 16/09/2014

  10. Some formulae on the site below, but is for single phase transformer. 3 Phase kVA = SqRt3 x VL x IL, and Power, Watts = kVA x power factor, where:- VL = Line volts, (Phase to...

    1 Answers · Science & Mathematics · 01/09/2014

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