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  1. Well, edit : thanks for Randy's answer, nevertheless he is not correct Sum [ (x_i)^2 ] = sum [ b^2 x_i^2 = b^2 sum x_i^2. expresses : VarX = Sum [ (x_i)^2 ] which is only correct if E(X) = 0...

    2 Answers · Science & Mathematics · 19/03/2016

  2. ...32π / 3 ) * ( 8 - 4√3 ) ..... Ans Note. tan^2 15° = 7 - 4√3 pf : By the formula : tan ( β / 2 ) = ± √ [ ( 1 - cos β ) / ( 1 + cos β ) ] ...

    1 Answers · Science & Mathematics · 27/02/2016

  3. 3t + 4s = 20 A = (1/2) * t * sqrt(t^2 - (t/2)^2) + s^2 A = (1/2) * t * t * sqrt(1 - 1/4) + s^2 A = (1/2) * t^2 * sqrt(3)/2 + s^2 A = (sqrt(3) / 4) * t^2 + s^2 3t + 4s = 20 3t = 20 - 4s t = (4/3) * (5 - s) A = (sqrt(3)/4) * (4/3)^2 * (5 - s)^2 + s^2 A = (sqrt(3)/4) * (16/9) * (25 - 10s + s^2) + s^2 A = (16...

    2 Answers · Science & Mathematics · 17/01/2016

  4. ...focus, and Q(-3, y) be the projection of P onto the given directrix. PF = 2PQ √[(x - 3)² + y²] = 2|x + 3| (x - 3)² + y²...

    2 Answers · Science & Mathematics · 09/12/2015

  5. This is a linear decrease, since the decrease amount is constant (100). So, after t years, the number pf people will be P = 9000 - 100t

    2 Answers · Science & Mathematics · 09/11/2015

  6. ...-paintings-content-marketing%25252F&source=iu&pf=m&fir=1nQ8XVbDJ3SanM%253A%252CvisLaZH2khC3pM...

    2 Answers · Science & Mathematics · 29/10/2015

  7. ... P(x,y) is a point on the parabola, then d(P,L) = PF 1/2 - y = √ [ x^2 + ( y + 1/2 )^2 ] 1/4 - y + y^2 = x^2 + ( y + 1/2 )^2 1/4...

    1 Answers · Science & Mathematics · 15/09/2015

  8. ... = 2.28*10^9 lbs/km². Multiply this by the surface area pf 516*10^6 km² and you get 1.19*10^19 lbs. If we assume that...

    1 Answers · Science & Mathematics · 05/05/2015

  9. ... of BC & CA respectively. Drop a perpendicular PF on AB. To prove AF = FB. BD = DC. ...

    1 Answers · Science & Mathematics · 23/04/2015

  10. I(t) = V/R * (1-e^-Rt/L) = 60/12 * (1 - e^-3t) = 5 as t-> infinity Don't normally answer anonymous questions because I prefer to help people thoughtful enough to be grateful which is becoming very rare these days.

    1 Answers · Science & Mathematics · 12/04/2015

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