... on the 16 side, then its diameter would be 16, meaning that the

**perimeter of**the circle would be P = pi * diameter = 50.24, but you want half**of**the**perimeter of**...2 Answers · Science & Mathematics · 19/09/2010

The

**perimeter of a sector**is the sum of the arc length and two radii. If you ONLY...however, working backward from the answer: let x = degrees of vertex angle of sector arc length = (x/360)(2π*11) = 73.8 - 22 x ≈ 269.8º this is the...3 Answers · Education & Reference · 06/07/2013

... are 360 degrees total in

**a**circle, so the curved part**of**the**sector**is 80/360**of**the circumference. In...cm. Therefore, we can get the full**perimeter of**the**sector**by adding up the ...1 Answers · Science & Mathematics · 06/11/2010

...

**sector**includes the arc AND the sides. Imagine**a**slice**of**pizza as**a sector**. The**perimeter**includes both the crust and the two cut edges.3 Answers · Education & Reference · 25/07/2007

I suppose " sector " is the part of a circle like the part of a pizza, ok? well, then we have p = 16... of equation 2r² - pr + 2a = 0 with the values of a and p, we get 2r² - 16r + 2 * 15 = 0 r² -8r...

1 Answers · Science & Mathematics · 12/01/2013

... you are looking at 1/3

**of a**circle. To calculate the**perimeter of a**circle you use: P = 2 * Pi * r in which 'r' is the radius...2 Answers · Science & Mathematics · 02/06/2012

70º is 70/360 = 7/36 of the full circle so its arc length is 7/36 of the whole circumference, which is 10π. So 7/36 • 10π = 70π/36 or 35π/18, plus the two radii of 5 each, gives a perimeter of 10 + 35π/18 cm.

1 Answers · Education & Reference · 04/01/2012

A sector of angle 5π/12 radians is cut from a circle of radius 6 cm. For the full circle, the angle is 2π radians and the perimeter is the circumference which is 2πr, i.e...

3 Answers · Science & Mathematics · 17/04/2010

...the total distance around the two dimensional figure. If it is

**a**circle ,**perimeter**is the circumference. If it is**a sector**, then it is 2 X radius + length**of**the arc Radius = 8cm circumference = 2 X 3.14 X 8 = 50.24 cm...2 Answers · Science & Mathematics · 02/08/2012

**perimeter of a sector**is 2r + r * theta = 40 r theta = 40-2r theta =(40-2r)/r**A**=theta/2 * r^2**A**[r]=(40-2r)/2r * r^2 = (40-2r)r/2=20r-r^2**A**'[r]=20-2r=0 r=102 Answers · Science & Mathematics · 18/03/2012