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  1. You multiply the probability of each outcome with the expected winnings. So: $500 * 1/1000 for the 3 digit = .5 $5000*1/10000 for the 4 digit = .5 There is no difference as to which game you play.

    2 Answers · Science & Mathematics · 21/10/2007

  2. ...may help you apply the same principals to the Ohio lottery : The odds of winning the record... show that any jackpot winner for this specific lottery has less than a 3% chance of being the...

    1 Answers · Science & Mathematics · 05/07/2013

  3. ...come closer to half and half. It is simply a coincidence that the lottery numbers have been starting with the same digit for a few ...

    7 Answers · Science & Mathematics · 19/03/2007

  4. E(pick4) = 0.0001*5000 - 0.9999*1 = 0.5 - 0.9999 = -0.4999 E(pick3) = 0.001*500 - 0.999*1 = 0.5 - 0.999 = -0.499 E(pick3) > E(pick4) answer = better off playing PICK 3.

    1 Answers · Science & Mathematics · 08/03/2008

  5. 1) 27, 284 /1500 = 18.189 ANSWER 19 guards 2) 265,000,000 / 7 = 37,857,142 $

    4 Answers · Science & Mathematics · 15/02/2013

  6. Probability of getting at least one correct number is complement of the probability of getting no correct number. The probability of getting every number incorrect is (9/10)^7. So probability of getting at one correct...

    3 Answers · Science & Mathematics · 12/12/2010

  7. if you are doing both then: you have 8/9 chances of being wrong with every draw so (8/9)^7=.438462386 so your chances of being right one time would be (1-.438462386)*100=56.1537614% if you are doing one or the other then: Pick 3: 8/9 of being wrong...

    4 Answers · Science & Mathematics · 12/12/2010

  8. ...make sense for the expected payout of any type of gamble to be positive, otherwise lotteries and casinos would go out of business.

    4 Answers · Science & Mathematics · 06/03/2008

  9. ...each winner change if more workers had participated in the lottery pool? If fewer workers had participated...

    1 Answers · Science & Mathematics · 18/10/2016

  10. The games are equivalent in terms of expected winnings. In the first game: E(X) = 5000/10000 = $0.50 In the second game: E(X) = 500/1000 = $0.50 The expected value is...

    1 Answers · Science & Mathematics · 21/10/2007

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