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  1. https://www.khanacademy.org/ Well, this site isn't like mathway ,but they do help your understanding in math. They do ...

    3 Answers · Education & Reference · 22/02/2013

  2. http://www. mathway .com/ I clicked on it and got through no problem try again with this address.just click on the blue good lluck. have a great day

    2 Answers · Yahoo Products · 26/01/2010

  3. http://www.algebra.com/ http://www. mathway .com/ http://www.analyzemath.com/Calculators.html http://www.algebra.com/services/rendering/simplifier.mpl Hope it helps!! :)

    9 Answers · Science & Mathematics · 07/03/2009

  4. Well, I did an acronym search and the only thing that came up is :Quaker Youth Theater. Somehow that doesn't seem to match with a site named " mathway .com", but you never know!

    2 Answers · Education & Reference · 06/12/2011

  5. Not a scam. Legitimate website. http://www.mywot.com/en/scorecard/ http://safeweb.norton.com/report/show?url= Mathway .com http://www.siteadvisor.com/sites/ mathway .com

    4 Answers · Computers & Internet · 06/05/2010

  6. Mathway is free my friend.

    4 Answers · Science & Mathematics · 26/10/2011

  7. www.algebra.com www.mathsupport.com www.quickmath.com www.webmath.com www.algebra-answer.com www.solvemymath.com i hope these are enough!

    1 Answers · Education & Reference · 08/07/2009

  8. www.purplemath.com

    1 Answers · Education & Reference · 25/02/2009

  9. Potato farms are still alive!

    3 Answers · Yahoo Products · 09/10/2012

  10. lim(x→∞) [√(0.25x^2 + 1) - 1]/(0.5x) = lim(x→∞) [√(0.25x^2 + 1) - 1] * [(√(0.25x^2 + 1) + 1] / {0.5x [(√(0.25x^2 + 1) + 1]} via conjugates = lim(x→∞) [(0.25x^2 + 1) - 1] / {0.5x [(√(0.25x^2 + 1) + 1]} = lim(x→∞) 0.5x / [(√(0.25x^2 + 1) + 1]. Now, divide each term by x = √x^2: lim(x→∞) 0.5 / [(√(0.25 + 1/x^2...

    1 Answers · Science & Mathematics · 20/08/2012

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