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1. ### A 10.0 L sample of gas is stored at 298 K and 12 .2 atm. How many mol of gas are present in the sample? A. 0.3?

V = 10 L T = 298 K P = 12 .2 atm R = 0.082 L.atm/mol. K PV = nRT n = PV/RT = 12 .2*10/0.082.298 n = 4.99 mol (C)

4 Answers · Science & Mathematics · 28/04/2011

2. ### Consider the reaction: SO2(g) + NO2(g) ⇌ SO3(g) + NO(g); K = 12 .00?

at equilibrium pressure SO3 = pressure NO = 0.500-x and pressure SO2 = pressure NO2 = x if K is Kp 12 .00 = (0.500-x) (0.500-x)/ x^2 square root 3.46 = 0.500-x/x 3.46x = 0.500-x x = 0.112 atm

1 Answers · Science & Mathematics · 09/04/2009

3. ### Consider the reaction: SO2(g) + NO2(g) ⇌ SO3(g) + NO(g); K = 12 .00?

at equilibrium pressure SO3 = pressure NO = 0.500-x pressure SO2 = pressure NO2 = x 12 .00 = (0.500-x)^2/ x^2 square root 3.464 = 0.500-x/x 3.464 x = 0.500 -x 4.464 x = 0.500 x =0.112 atm = pressure SO2

1 Answers · Science & Mathematics · 09/04/2009

4. ### When 12 .034g of K was reacted with an excess of Oxygen, a 27.10% yield of K2O was obtained. How many grams....

moles K = 12 .034 g / 39.0983 g/mol = 0.3078 the ratio between K and K2O is...

1 Answers · Science & Mathematics · 02/06/2008

5. ### if k = 1x10^- 12 then the reaction system at equilibrium contains mostly?

... very small so the reaction system contains mostly reactants.... K = [products] / [reactants] where [ ] represents conc. as...

1 Answers · Science & Mathematics · 23/05/2012

6. ### A gas at 350 K and 12 atm has a molar volume 12 per cent larger than that calculated from the perfect gas law.?

...an ideal gas at those conditions. The actual molar volume is 12 % greater so you know the actual molar volume. The equation for a real gas...

1 Answers · Science & Mathematics · 16/09/2014

7. ### The half-life of tritium is 12 .3 y. What is the first order rate constant, k , for tritium?

Half-life and first order rate constant are related as: k = ln(2) / t½ For this reaction: k = ln(2) / 12 .3y = 0.056y⁻¹ So C.0.056/y is the correct answer

1 Answers · Science & Mathematics · 13/05/2009

8. ### a student places 1.854 g of a diatomic gas into a 1. 12 L container at 272 K .?

... Solving for n: n = (PV) / (RT) n = (0.977)(1. 12 ) / [(0.08205746)(272)] <=== Note that R has values of L*atm / (mol * K ) n = 0.0490 moles MW = (1.854 g / 0.0490 moles) MW...

1 Answers · Science & Mathematics · 07/03/2011

9. ### Need help solving Multi-step Equations 6(2-10k) = -11( k -10)?

6(2-10 k ) = -11( k -10) 12 - 60k = -11k 110 \\ expanded the terms 60k = -11k 98 \... terms were expanded wrong. It should be: -11*( k -10) = -11k 110 Because a minus times a minus is positive...

1 Answers · Science & Mathematics · 31/01/2014

10. ### hat is the pK (= −log K ) at 25°C for the reaction below? 2 ClO3−(aq) + 12 H+(aq) + 5 Mg(s) « Cl2(g) + 6 H2O(l)?

Eo = 0.059/n log K In the written reaction, 5Mg(s) ==> 5Mg2+(aq), so that's a 10-electron change = n. log K = nEo / 0.059 = (10)(3.840) / 0.059 = 651 -log K = pK = -654

1 Answers · Science & Mathematics · 01/05/2012