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V = 10 L T = 298

**K**P =**12**.2 atm R = 0.082 L.atm/mol.**K**PV = nRT n = PV/RT =**12**.2*10/0.082.298 n = 4.99 mol (C)4 Answers · Science & Mathematics · 28/04/2011

at equilibrium pressure SO3 = pressure NO = 0.500-x and pressure SO2 = pressure NO2 = x if

**K**is Kp**12**.00 = (0.500-x) (0.500-x)/ x^2 square root 3.46 = 0.500-x/x 3.46x = 0.500-x x = 0.112 atm1 Answers · Science & Mathematics · 09/04/2009

at equilibrium pressure SO3 = pressure NO = 0.500-x pressure SO2 = pressure NO2 = x

**12**.00 = (0.500-x)^2/ x^2 square root 3.464 = 0.500-x/x 3.464 x = 0.500 -x 4.464 x = 0.500 x =0.112 atm = pressure SO21 Answers · Science & Mathematics · 09/04/2009

moles

**K**=**12**.034 g / 39.0983 g/mol = 0.3078 the ratio between**K**and K2O is...1 Answers · Science & Mathematics · 02/06/2008

... very small so the reaction system contains mostly reactants....

**K**= [products] / [reactants] where [ ] represents conc. as...1 Answers · Science & Mathematics · 23/05/2012

...an ideal gas at those conditions. The actual molar volume is

**12**% greater so you know the actual molar volume. The equation for a real gas...1 Answers · Science & Mathematics · 16/09/2014

Half-life and first order rate constant are related as: k = ln(2) / t½ For this reaction: k = ln(2) / 12 .3y = 0.056y⁻¹ So C.0.056/y is the correct answer

1 Answers · Science & Mathematics · 13/05/2009

... Solving for n: n = (PV) / (RT) n = (0.977)(1.

**12**) / [(0.08205746)(272)] <=== Note that R has values of L*atm / (mol ***K**) n = 0.0490 moles MW = (1.854 g / 0.0490 moles) MW...1 Answers · Science & Mathematics · 07/03/2011

6(2-10

**k**) = -11(**k**-10)**12**- 60k = -11k 110 \\ expanded the terms 60k = -11k 98 \... terms were expanded wrong. It should be: -11*(**k**-10) = -11k 110 Because a minus times a minus is positive...1 Answers · Science & Mathematics · 31/01/2014

Eo = 0.059/n log

**K**In the written reaction, 5Mg(s) ==> 5Mg2+(aq), so that's a 10-electron change = n. log**K**= nEo / 0.059 = (10)(3.840) / 0.059 = 651 -log**K**= pK = -6541 Answers · Science & Mathematics · 01/05/2012

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