...block if n is not congruent to −1 modulo p. For 2 ≤ k ≤ p, d^ k /dz^ k will have Jordan blocks given by decomposing these blocks as above...

1 Answers · Science & Mathematics · 03/05/2008

Consider ∫c e^(isz) dz/(z^2 + k ^2), where C is a semicircular contour in the upper...z = 0) with radius R > 0 sufficiently large (we use Jordan 's Lemma to show that the integral on the circular...

1 Answers · Science & Mathematics · 04/12/2013

... the box can be chosen with arbitrarily small

**Jordan**content, the**Jordan**content of {u_**k**|**k**in the natural numbers} must be 0.1 Answers · Science & Mathematics · 26/04/2012

Let J(n,

**k**) denote the nxn**Jordan**block having the single eigenvalue**k**. (So J..._n^(-1) = S_n and that S_n J(n,**k**) S_n = J(n,**k**)^T. So, this ...1 Answers · Science & Mathematics · 08/08/2013

Using synthetic division 3.|.1..-

**k**.......7.......-12 ....1..3-**k**..16-3k...36 - 3k 36 - 3k = 0, so**k**= 124 Answers · Science & Mathematics · 03/04/2012

...2^( k +1)). J_ k covers 1/ k and |J_ k | = ε/2^ k . So the sum |J_1| + |J_2| + |J_3| + ... ... we can choose ε to be arbitrarily small, the set must have Jordan content 0.

1 Answers · Science & Mathematics · 25/11/2013

...epsilon;. Perhaps ∪[j/n,(j+1)/n)x[

**k**/n,(**k**+1)/n)x[**k**/n,(**k**+1)/n) for**k**=0 to n and j=0 to n, which has**Jordan**content: (n+1)²/n³ which is less than ε for every n greater...1 Answers · Science & Mathematics · 05/12/2013

...bottom equation is just double the first equation. 2 7 7 |4 4 14 14|

**k**divide the second formula by two and you will have 2 7 7 |4 2 7 7 |(**k**/2...2 Answers · Science & Mathematics · 16/03/2011

To obtain the solution using Gauss-

**Jordan**algorithm, it requires O(n^3) operations. You're...2 Answers · Science & Mathematics · 07/01/2009

...the 3rd...to get new 2nd : -14 z + 11 w = -14 and new 3rd : 7 z + (

**k**-6) w = 7...multiply new 2nd by [1/2] and add to new 3rd to get (**k**- 6...1 Answers · Science & Mathematics · 11/03/2008