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  1. ... stripped of their electrons. So we really have hydrogen ions merging to form helium ions (alpha particles) during...

    7 Answers · Science & Mathematics · 29/07/2019

  2. Doppler applies. For a stationary receiver, f = F₀*c/(c + v) ← v -ve if src moving toward rcvr Since the frequency is shifted upward, Altair is moving toward us, and so (4.57e14 + 3.98e10) Hz = 4...

    1 Answers · Science & Mathematics · 22/08/2019

  3. An excited state has more energy. The term "ground state" means lowest energy state.

    1 Answers · Science & Mathematics · 19/05/2019

  4. The energy of the n=1 level is -13.6 eV relative to the electron being at infinity. So the required energy (ionization energy) is 13.6 eV.

    3 Answers · Science & Mathematics · 01/06/2019

  5. Prior to quantum mechanics we thought of the electron as orbiting in circles around a nucleus. The orbital speed could be calculated from kQq/ r^2 = m v^2/r But there were problems with this model. It would certainly...

    3 Answers · Science & Mathematics · 28/05/2019

  6. For a stationary receiver (observer), new frequency f = F₀*c/(c + v) ← v -ve if src moving toward rcvr using c = 299 792 458 m/s, new f = 6.17e14Hz * 299792458m/s / (299792458m/s - 3.01e5m/s) new f = 617620107836264.23161624863437674 Hz and so the shift is Δf = f - F₀...

    1 Answers · Science & Mathematics · 26/08/2019

  7. change in energy = R(1/3² - 1/5²) = 1.55e-19 J and change in energy = hv / λ so λ = hv / change in energy = 6.626e−34J·s * 2.998e8m/s / 1.55e-19J λ = 1.282e-6 m = 1.282 µm = 1282 nm

    2 Answers · Science & Mathematics · 14/06/2019

  8. ... if the graph shows the light before or after passing through the hydrogen. b) The phrase “connect the wavelengths...” is meaningless...

    1 Answers · Science & Mathematics · 01/09/2019

  9. ...intro on how the process takes place. Firstly the cloud of hydrogen(deuterium/tritium)gas combine together and compress itself due to its own mass...

    6 Answers · Science & Mathematics · 31/07/2019

  10. To a good approximation v/c = Δf/f₀ v = cΔf/f₀ = 3x10^8 x 4.26x10^10/(6.17x10^14) = 2.07x10^4 m/s By the way, it's 'Hz', not 'hz'.

    3 Answers · Science & Mathematics · 22/07/2019

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