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I'll take the 1st question. dq/dt = -kq, where q = current concentration minus asymptotic concentration (exponential decay) q(t) = q(0) * e^(-kt) Rate constant k = 80/(60*100000) = 1.33333E-5 s^-1 (Time constant = 75000 s) y(asymptote) = 0.005 y(0) = 0.001: q(0) = y(0)-y(asymptote) y(t) = 0.002: q(t) = y(t)-y...

2 Answers · Science & Mathematics · 24/12/2008

I'll take the 1st question. dq/dt = -kq, where q = current concentration minus asymptotic concentration (exponential decay) q(t) = q(0) * e^(-kt) Rate constant k = 80/(60*100000) = 1.33333E-5 s^-1 (Time constant = 75000 s) y(asymptote) = 0.005 y(0) = 0.001: q(0) = y(0)-y(asymptote) y(t) = 0.002: q(t) = y(t)-y...

1 Answers · Science & Mathematics · 24/12/2008

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**2010**/05/13/algae-hydrogen-fuel.html Such ...below reports efficiencies of 50–80%.**Heat**(high Temperature, over 1000ºC is...1 Answers · Science & Mathematics · 21/08/2012

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