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The position vector r traces out an ellipse with semi-major axis a and semi-minor axis b. The parametric equation for r(t) is given. By differentiating r with respect to time you find the velocity vector. A second differentiation gives the acceleration...

What makes this question seem very silly is that nobody would pull on the wrench in that direction.  He would pull on it in a direction perpendicular to the wrench.  Oh, but then the physics problem would be too easy, right? OK, so let's say some nincompoop actually does pull on...

(a) volume flow rate everywhere is Q = vA = 8.00m/s * (0.500m)² = 2.00 m³/s (b) The velocity at the exit is V = Q/A' = 2.00m³/s / (0.200m)² = 50.0 m/s V² = v² + 2ad (50.0m/s)² = (2.00m/s)² + 2*a*2.00m...

Bernoulli: p₀ + ρgh₀ + ½ρv₀² = p₁ + ρgh₁ + ½ρv₁² h terms cancel on the level table. If the velocity under the paper (v₀) is GREATER THAN the velocity over the...

(a) ω² = ω₀² + 2αΘ 0² = (19.7rad/s)² + 2*α*3.86 rad α = -50.3 rad/s² (b) t = Δω / α = (0 - 19.7)rad/s / -50.3rad/s² = 0.392 s

sum of currents into a node have to add to zero 7 – Ia – Ic = 0 Ic + Id – Ib = 9 Ia = 2 A and Id = 3 A 7 – 2 – Ic = 0Ic + 3 – Ib = 9 Ic = 5 amp 5 + 3 – Ib = 9 Ib = 5 + 3 – 9 = –1 amp

It looks to me like a stable equilibrium. If initially centered on the rollers, it should remain centered. If slightly perturbed, the normal (and therefore friction) force on the "long" side of the board will increase producing a...

...you can do a rotation without also doing a translation. To rotate the bottom figure , you would rotate it about its center of axis - but that would not align it with the...